B1.1 Carbohydrates and lipids

SL & HLSL and HL · Molecules · Theme B

Big questions

  • Why can small changes in the shape of a sugar or lipid molecule give it a completely different job?
  • When should an organism store energy as carbohydrate and when as fat?

Carbon compounds and SI prefixes

SL & HLSyllabus understandings: B1.1.1

Almost every molecule made by living organisms is built on a framework of carbon atoms. The reason lies in how carbon bonds.

Covalent bonds

A covalent bond forms when two atoms share a pair of electrons. A carbon atom has four electrons in its outer shell, so it forms up to four covalent bonds:

  • four single bonds, as in methane (CH₄) or in each –CH₂– of a fatty acid chain; with four single bonds the bonds point to the corners of a tetrahedron, so molecules are three-dimensional;
  • or a combination of single and double bonds, as in C=C in unsaturated fatty acids and C=O in carboxyl groups (a double bond shares two pairs of electrons).

Carbon bonds with other carbon atoms and with atoms of other non-metals, especially hydrogen, oxygen, nitrogen and phosphorus (and sulfur). Because carbon–carbon bonds are stable, carbon atoms can link into structures of almost any size and shape:

Shape of the carbon skeleton Example in this topic
Unbranched chain fatty acids; amylose and cellulose (chains of rings)
Branched chain amylopectin and glycogen
Single ring glucose, fructose, ribose
Several fused rings steroids such as cholesterol and oestradiol

SI prefixes: an international convention

Biologists measure things from the size of molecules to the energy in food stores, so they use the SI (International System of Units). Its units and prefixes are fixed by international agreement, so a measurement means exactly the same to every scientist in every country.

Prefix Symbol Multiplies the unit by Example
kilo k 10³ (1,000) fat releases about 37 kJ g⁻¹
centi c 10⁻² (1/100) seal blubber can be several cm thick
milli m 10⁻³ (1/1,000) blood glucose is about 5 mmol dm⁻³
micro μ 10⁻⁶ (1/1,000,000) a fat-storing cell can be about 100 μm across
nano n 10⁻⁹ (1/1,000,000,000) a glucose molecule is about 1 nm across

Condensation and hydrolysis

SL & HLSyllabus understandings: B1.1.2 · B1.1.3

Many biological molecules are macromolecules: very large molecules that are polymers, chains of smaller subunits called monomers.

Condensation builds polymers

Monomers are linked by condensation reactions. Two molecules are joined by a new covalent bond, and a molecule of water is released: an –OH is removed from one molecule and an –H from the other. In cells these reactions are catalysed by enzymes and need an input of energy.

Polymer Monomers Bond made by condensation
Polysaccharide (starch, glycogen, cellulose) monosaccharides glycosidic bond
Polypeptide (protein) amino acids peptide bond
Nucleic acid (DNA, RNA) nucleotides phosphodiester bond (sugar–phosphate)

Two α-glucose molecules join by condensation to form the disaccharide maltose: the –OH on carbon 1 of one glucose and the –H of the –OH on carbon 4 of the other form water, and the remaining oxygen links the two rings by a 1,4 glycosidic bond. Repeating this many times builds starch or glycogen. For nucleic acids, see A1.2 Nucleic acids.

Condensation and hydrolysis
OCH₂OH14OCH₂OH14two α-glucose molecules (monomers)OHOHH₂O1,4 glycosidic bondwater releasedglycerol + three fatty acidsH₂COHHOCOH₂OHCOHHOCOH₂OH₂COHHOCOH₂O3 ester bondshydrocarbon chainsWater released: 0
Text description of this animation

Part 1 shows two alpha-glucose molecules drawn as hexagonal rings, with only the reacting groups shown. In condensation, the –OH on carbon 1 of the left glucose and the H from the –OH on carbon 4 of the right glucose are removed and form a water molecule; the remaining oxygen links the two rings, making a 1,4 glycosidic bond, and the product is the disaccharide maltose. In hydrolysis a water molecule is used: it splits into –OH, which goes to carbon 1, and –H, which goes to the oxygen on carbon 4, giving two glucose molecules again. Part 2 shows glycerol and three fatty acids. In three condensation reactions the –OH of each fatty acid's carboxyl group and an H from one of glycerol's –OH groups form water, and the fatty acid joins the glycerol by an ester bond. The products are one triglyceride and three water molecules.

  1. Two α-glucose molecules. Two alpha-glucose monomers. The groups that will react are circled - the –OH on carbon 1 of the left molecule and the –OH on carbon 4 of the right molecule.
  2. Condensation forms maltose. The –OH from carbon 1 and the H from the other –OH join to form water, which is released. The remaining O now links carbon 1 to carbon 4 - a 1,4 glycosidic bond. The disaccharide is maltose. Adding more glucose the same way builds starch or glycogen.
  3. Hydrolysis splits maltose. Hydrolysis is the reverse. A water molecule is used up - it splits into –OH, which bonds to carbon 1, and –H, which bonds to the O left on carbon 4. Two glucose monomers are released. Digestion of starch works like this.
  4. Glycerol and three fatty acids. Glycerol has three –OH groups. Each fatty acid has a carboxyl group (–COOH) at one end of its hydrocarbon chain.
  5. Three condensations make a triglyceride. Each fatty acid's –OH and an H from one of glycerol's –OH groups form water. The fatty acid joins the glycerol by an ester bond. Three condensation reactions make one triglyceride and release three water molecules.

Hydrolysis breaks polymers

Hydrolysis (“splitting with water”) is the reverse of condensation. A covalent bond between two monomers is broken and a water molecule is used up. The water molecule is split: its –H is added to one product and its –OH to the other, so each monomer gets back the group it lost. Digestion depends on hydrolysis, catalysed by enzymes:

  • polysaccharides + water → monosaccharides (for example amylase hydrolyses starch to maltose, and maltase hydrolyses maltose to glucose);
  • polypeptides + water → amino acids (proteases);
  • triglycerides + water → fatty acids + glycerol (lipase).

Monosaccharides and glucose

SL & HLSyllabus understandings: B1.1.4

Carbohydrates and lipids in 3D
Ring forms of alpha-glucose and beta-glucoseTwo hexagonal rings, each with five carbons numbered 1 to 5 and an oxygen at the top right. Carbon 6, as a CH2OH group, is above carbon 5. Going round from carbon 1, the groups above and below the ring are: carbon 2, H above and OH below; carbon 3, OH above and H below; carbon 4, H above and OH below; carbon 5, CH2OH above and H below. In alpha-glucose carbon 1 has H above and OH below. In beta-glucose carbon 1 has OH above and H below.HOHHOHOHHHOHH6 CH₂OHCOCCCC12345α-glucoseOHHHOHOHHHOHH6 CH₂OHCOCCCC12345β-glucose–OH on C1:α below,β above
  1. Ring of five carbon atoms and one oxygen atom; carbon 6 (CH₂OH) lies outside the ring, above carbon 5.
  2. α-glucose: the –OH on carbon 1 is below the ring, on the opposite side to the CH₂OH.
  3. β-glucose: the –OH on carbon 1 is above the ring, on the same side as the CH₂OH. Every other group is the same in both.
Text description of this visual

Three models. The first shows alpha-glucose (left) and beta-glucose (right) as ball-and-stick models: carbon atoms dark, oxygen red and hydrogen light grey. Each has a ring of five carbon atoms and one oxygen atom, drawn flat as in exam diagrams, with a faint plate marking the plane of the ring. Carbon 6 (a CH₂OH group) is above the ring on carbon 5. The only difference between the two forms is on carbon 1: in alpha-glucose the –OH is below the ring, in beta-glucose it is above. The second model shows polysaccharides, each glucose drawn as a hexagonal tile with a red bead for the ring oxygen and a dark stub for carbon 6: amylose, an unbranched chain of alpha-glucose coiled into a helix; amylopectin, chains of alpha-glucose joined by 1,4 bonds with occasional 1,6 branches (blue links); glycogen, the same but much more highly branched and compact; and cellulose, straight parallel chains of beta-glucose in which every other glucose is turned over, held together side by side by hydrogen bonds (dashed blue). The third model shows a triglyceride (glycerol joined by three ester bonds to three fatty acids), a phospholipid (glycerol, two fatty acids and a phosphate group), three fatty acids with 18 carbons (saturated and straight; trans-unsaturated and still straight; cis-unsaturated with a bend at the double bond), and the steroid hormone oestradiol with its four fused rings.

α- and β-glucose

α-glucose
Alpha-glucose, C₆H₁₂O₆, in its ring form. It is the monomer of starch and glycogen. Its –OH on carbon 1 is below the plane of the ring.
β-glucose
Beta-glucose has exactly the same atoms and the same groups on carbons 2 to 6. Only carbon 1 differs, with its –OH above the ring. It is the monomer of cellulose.
Carbon 1 in α-glucose (–OH below)
In alpha-glucose the –OH on carbon 1 points below the ring, on the opposite side to the CH₂OH group. Carbon 1 is the carbon that forms glycosidic bonds with other sugars.
Carbon 1 in β-glucose (–OH above)
In beta-glucose the –OH on carbon 1 points above the ring, on the same side as the CH₂OH group. This small difference makes cellulose chains straight instead of helical.
Carbon 2
Carbons are numbered from carbon 1, clockwise round the ring as drawn. Carbon 2 carries an –OH below the ring and an H above it, in both alpha- and beta-glucose.
Carbon 3
Carbon 3 carries an –OH above the ring and an H below it.
Carbon 4
Carbon 4 carries an –OH below the ring. In maltose, starch, glycogen and cellulose, this –OH takes part in the 1,4 glycosidic bond to carbon 1 of the next glucose.
Carbon 5
The last carbon in the ring, next to the ring oxygen. It carries carbon 6 above the ring and an H below it. Numbering is the same in both forms.
Carbon 6 (CH₂OH)
Carbon 6 is outside the ring, in a CH₂OH group above carbon 5. It is used in 1,6 glycosidic bonds, which form the branch points of amylopectin and glycogen.
Ring oxygen
One oxygen atom is part of the ring, between carbon 1 and carbon 5. A hexose ring has five carbons and this oxygen; the sixth carbon is outside the ring.
Hydroxyl (–OH) groups
Glucose has five –OH groups. They are polar and form hydrogen bonds with water, which is why glucose is so soluble and can be carried dissolved in blood plasma.

Starch, glycogen and cellulose

Amylose (starch)
An unbranched chain of alpha-glucose joined by 1,4 glycosidic bonds. The angle of the alpha bonds makes the chain coil into a compact helix, about six glucose units per turn.
Amylopectin (starch)
Chains of alpha-glucose joined by 1,4 bonds, with 1,6 bonds making branches (roughly one every 20–30 glucose units). Branching makes the molecule compact and gives it many chain ends.
Glycogen
The energy store of animals and fungi. Like amylopectin, but more highly branched (about every 8–12 glucose units), so it is even more compact and has even more chain ends.
Cellulose
Unbranched chains of beta-glucose joined by 1,4 glycosidic bonds. Each chain is straight, so chains can lie parallel and close together, forming the main material of plant cell walls.
α-glucose units
In starch and glycogen every glucose unit is alpha-glucose, and all the units in a chain face the same way (here the ring oxygen bead and CH₂OH stub are on the same side of each tile).
β-glucose units
In beta-glucose the –OH groups on carbons 1 and 4 are on opposite sides of the ring, so each unit must be turned over relative to its neighbour to link up. The ring O and CH₂OH alternate sides.
1,4 glycosidic bond
A covalent C–O–C link between carbon 1 of one glucose and carbon 4 of the next, made by a condensation reaction that releases a water molecule. It is broken by hydrolysis.
1,6 glycosidic bond (branch point)
Carbon 1 of the first glucose in a branch joins carbon 6 of a glucose in another chain. These bonds create the branches of amylopectin and glycogen; amylose and cellulose have none.
Chain ends
Glucose is added to, or removed from, the chain ends that have a free carbon 4 (each molecule has only one end with a free carbon 1). Many branches mean many ends, so a store can be built or mobilized quickly.
Hydrogen bonds between chains
–OH groups on one cellulose chain form hydrogen bonds with oxygen atoms on the neighbouring chain. Each is weak, but millions of them cross-link the chains into a strong bundle.
Microfibril
Many straight cellulose chains lie parallel in layers and are hydrogen-bonded into a bundle called a microfibril, a few nanometres wide. Microfibrils have very high tensile strength.

Lipids

Triglyceride
A fat or oil molecule, made of one glycerol and three fatty acids joined by three ester bonds. It is almost entirely hydrocarbon, so it is hydrophobic and insoluble in water.
Glycerol
A three-carbon molecule with an –OH group on each carbon. In a triglyceride all three –OH groups have formed ester bonds; in a phospholipid two have joined fatty acids and one a phosphate.
Ester bond
The C–O–C(=O) link between glycerol and a fatty acid. Each one is made by a condensation reaction between an –OH of glycerol and the –COOH of a fatty acid, releasing one water molecule.
Hydrocarbon chains (hydrophobic)
Long chains of carbon and hydrogen atoms. C–H bonds are almost non-polar, so these chains do not form hydrogen bonds with water. They release a lot of energy when oxidized in respiration.
Phospholipid
Glycerol joined to two fatty acids and one phosphate group. It is amphipathic, with a hydrophilic phosphate head and two hydrophobic tails, so in water it forms bilayers.
Phosphate group (hydrophilic)
Phosphorus (orange) bonded to four oxygen atoms, attached to the third carbon of glycerol. It is charged, so it attracts water. In most membrane phospholipids another polar group is attached to it.
Carboxyl group (–COOH)
The acid group on carbon 1 of every fatty acid. It reacts with an –OH of glycerol in a condensation reaction to form an ester bond.
Saturated fatty acid
Stearic acid, 18 carbons. All carbon–carbon bonds are single, so every carbon holds as many H atoms as possible. The chain is straight, so molecules pack tightly and melt at a high temperature (69 °C).
Trans fatty acid
One C=C double bond with its two H atoms on opposite sides. The chain stays almost straight, so it packs nearly as well as a saturated chain. Trans fats are uncommon in nature.
Cis fatty acid (kinked)
Oleic acid, monounsaturated. At the C=C double bond both H atoms are on the same side, which bends the chain. Bent chains cannot pack closely, so oleic acid melts at only about 13 °C.
Kinked phospholipid tail
Phospholipids often have one cis-unsaturated tail. The bend stops the tails packing tightly, which keeps membranes fluid.
Steroid ring system
Oestradiol, a steroid hormone. All steroids share four fused rings of carbon atoms, three with six carbons and one with five. The molecule is almost all hydrocarbon, so it is non-polar.
Hydroxyl groups of oestradiol
Oestradiol has only two –OH groups, one at each end. They are too few to make the molecule water-soluble, so it can dissolve in and diffuse through the hydrophobic core of a membrane.

Monosaccharides are single sugar units: the monomers of carbohydrates. They contain carbon, hydrogen and oxygen, typically in the ratio 1 : 2 : 1, so pentoses (five carbons) have the formula C₅H₁₀O₅ and hexoses (six carbons) C₆H₁₂O₆. In water, most pentose and hexose molecules close up into a ring that contains one oxygen atom; the remaining carbons carry –H, –OH or –CH₂OH groups.

Recognizing pentoses and hexoses

To classify a ring diagram, count every carbon atom, including any outside the ring:

  • ribose (in RNA) is a pentose with a five-membered ring of four carbons and one oxygen, plus one carbon in a CH₂OH group;
  • glucose is a hexose with a six-membered ring of five carbons and one oxygen, plus carbon 6 in a CH₂OH group;
  • fructose is also a hexose, although its ring is five-membered: four carbons in the ring and two CH₂OH groups outside it.
Ring forms of a pentose and two hexosesThree monosaccharides in ring form. Ribose is a pentose: a five-membered ring of four carbons and one oxygen, with the fifth carbon in a CH2OH group outside the ring. Alpha-glucose is a hexose: a six-membered ring of five carbons and one oxygen, with the sixth carbon in a CH2OH group outside the ring. Fructose is also a hexose, but its ring is five-membered: four carbons and one oxygen in the ring, and two CH2OH groups outside it, carbons 1 and 6. Counting all the carbon atoms, not the ring corners, tells a pentose from a hexose.OHHHOHHOH5 CH₂OHHOCCCC1234Ribosepentose · 5 CC₅H₁₀O₅HOHHOHOHHHOH6 CH₂OHHCOCCCC12345Glucose (α)hexose · 6 CC₆H₁₂O₆OH1 CH₂OHOHHHOH6 CH₂OHHOCCCC2345Fructose (β)hexose · 6 CC₆H₁₂O₆
A pentose and two hexoses in ring form. Corners labelled C are carbon atoms; the red O is the ring oxygen. Fructose has a five-membered ring but six carbon atoms, so it is a hexose.

α-glucose and β-glucose

Glucose has two ring forms. In both, the ring oxygen lies between carbons 1 and 5, and carbon 6 (CH₂OH) is above the ring. They differ only at carbon 1: in α-glucose the –OH is below the ring; in β-glucose it is above. Rotate the 3D model to see this.

How glucose’s properties suit its uses

Property Why How it is used
Soluble in water five polar –OH groups form hydrogen bonds with water dissolves in the cytoplasm and in blood plasma
Easily transported small and soluble carried in blood plasma to every cell (in plants, sugar is moved as sucrose, a disaccharide of glucose and fructose)
Chemically stable does not break down or react readily at body temperature can be carried and stored without being lost, and converted to stable polysaccharides
High energy yield on oxidation many C–H and C–C bonds oxidized in cell respiration, releasing about 2,800 kJ per mole (about 16 kJ g⁻¹ for free glucose; glycogen, whose residues have each lost a water molecule, gives ≈ 17 kJ g⁻¹, the figure used below)

Starch, glycogen and cellulose

SL & HLSyllabus understandings: B1.1.5 · B1.1.6

Polysaccharides are polymers of monosaccharides. Switch the 3D model to Starch, glycogen and cellulose to compare their structures.

Starch and glycogen: energy stores

Plants store energy as starch, in starch grains in seeds, tubers and many other cells. Animals, and also fungi, store glycogen, mainly in the liver and in muscles. Both are made of α-glucose:

  • Amylose (about 20–30% of starch) is an unbranched chain of α-glucose joined by 1,4 glycosidic bonds. The angle of the bonds makes the chain coil into a helix.
  • Amylopectin (the rest of starch) has 1,4 chains with 1,6 glycosidic bonds forming branches, roughly every 20–30 glucose units.
  • Glycogen is like amylopectin but more highly branched, about every 8–12 units.

They make good energy stores because:

  1. Compact: coiling and branching pack many glucose units into a small space.
  2. Relatively insoluble: their molecules are very large, so they hardly dissolve and do not draw water into cells by osmosis.
  3. Easily built up and broken down: α-glucose can be added to, or removed from, the ends of the chains by condensation and hydrolysis. Branched molecules have many ends, so a store can be mobilized quickly when glucose is needed, for example from muscle glycogen during exercise.

Cellulose: a structural polysaccharide

Cellulose, the main material of plant cell walls, is made of β-glucose linked by 1,4 glycosidic bonds. In β-glucose the –OH groups on carbons 1 and 4 point to opposite sides of the ring, so to bond, each glucose is turned over relative to its neighbour. The alternating orientation produces a straight, unbranched chain.

Straight chains can lie side by side. –OH groups on neighbouring chains form hydrogen bonds, cross-linking many parallel chains into bundles called microfibrils, a few nanometres wide. Microfibrils have a very high tensile strength, which lets cell walls resist the pressure of water entering the cell. Most animals cannot hydrolyse the β-1,4 bonds; herbivores rely on microorganisms in their gut to do it.

Starch Glycogen Cellulose
Monomer α-glucose α-glucose β-glucose
Bonds 1,4 (amylose); 1,4 and 1,6 (amylopectin) 1,4 and 1,6 1,4 only
Shape helical, some branched highly branched straight chains in microfibrils
Function energy store in plants energy store in animals and fungi structural, in plant cell walls

Glycoproteins and cell–cell recognition

SL & HLSyllabus understandings: B1.1.7

A glycoprotein is a protein with one or more short carbohydrate chains (oligosaccharides) covalently attached. In the plasma membrane these chains project from the outer surface of the cell into the extracellular fluid (see B2.1 Membranes and membrane transport).

The sequence and branching of the sugars in these chains varies between cell types, between individuals and between species. Proteins on other cells, such as receptors and antibodies, can bind to particular carbohydrate structures, so the chains act as identity tags. This is cell–cell recognition. For example, the immune system uses cell-surface markers to tell the body’s own cells (self) from foreign or infected cells (non-self).

The ABO blood group antigens

The ABO antigens are carbohydrate chains on glycoproteins (and glycolipids) in the plasma membrane of red blood cells:

  • Almost everyone makes the H antigen, which ends in the sugars galactose and fucose.
  • People with an A allele make an enzyme that adds an extra sugar, N-acetylgalactosamine, to the H antigen, making the A antigen.
  • People with a B allele make a slightly different enzyme that adds galactose instead, making the B antigen.
  • People with blood group O have neither working enzyme, so their red blood cells carry only the H antigen. Group AB cells have both A and B antigens.
ABO antigens on red blood cellsThree patches of red blood cell membrane, each with a glycoprotein carrying a short carbohydrate chain on the outer surface. In group O the chain ends in the H antigen: N-acetylglucosamine, then galactose with a fucose attached. In group A one more sugar, N-acetylgalactosamine, is attached to that galactose. In group B a different extra sugar, galactose, is attached instead. People with group AB have both A and B antigens.Outside the cellCytoplasmGlcNAcGalFucGroup OH antigen onlyGlcNAcGalFucGalNAcGroup AA antigenGlcNAcGalFucGalGroup BB antigen
The end of the carbohydrate chain on a red blood cell glycoprotein. The A and B antigens differ from the H antigen of group O by a single extra sugar (Gal = galactose, GalNAc = N-acetylgalactosamine, GlcNAc = N-acetylglucosamine, Fuc = fucose).

The plasma of each person contains antibodies against the A or B antigens their own cells lack, so group A people have anti-B antibodies and group O people have both. If a patient receives red blood cells carrying an antigen they do not have, their antibodies recognize the cells as non-self and bind to them, making them clump together (agglutination). This is why blood for transfusion must be matched. (The inheritance of ABO blood groups is in D3.2 Inheritance.)

Lipids, triglycerides and phospholipids

SL & HLSyllabus understandings: B1.1.8 · B1.1.9

What makes a lipid

Lipids are a varied group of substances, defined by their solubility: they dissolve readily in non-polar solvents such as hexane or chloroform but are only sparingly soluble in water. Their molecules consist mostly of carbon and hydrogen joined by almost non-polar C–H and C–C bonds, with few polar or charged groups, so they form few hydrogen bonds with water: they are hydrophobic. The main groups are:

  • fats and oils (triglycerides), used for energy storage;
  • waxes, for example the waterproof cuticle on leaves;
  • phospholipids, which form membranes;
  • steroids, such as cholesterol and the sex hormones.

Triglycerides

A triglyceride is made from one glycerol molecule and three fatty acids. Glycerol has three –OH groups. A fatty acid has a long hydrocarbon chain with a carboxyl group (–COOH) at one end. Each fatty acid is joined to glycerol by a condensation reaction between its –COOH and one of glycerol’s –OH groups, releasing water and forming an ester bond. Three condensation reactions make one triglyceride and three water molecules. A triglyceride is not a polymer: it is not a chain of repeating monomers.

Phospholipids

A phospholipid is made in the same way, but glycerol is linked to only two fatty acids, by ester bonds; its third –OH is linked by condensation to a phosphate group. In most membrane phospholipids a further small polar group, such as choline, is attached to the phosphate.

Switch the 3D model to Lipids to see a triglyceride and a phospholipid side by side, and step through the second part of the animation above to watch the three condensation reactions.

Saturated and unsaturated fatty acids

SL & HLSyllabus understandings: B1.1.10

Fatty acids differ in the length of their hydrocarbon chain (often 14–20 carbons in animals and plants) and in the number of C=C double bonds in it:

  • Saturated fatty acids have only single bonds between carbon atoms, so each carbon holds as many hydrogen atoms as it can: the chain is “saturated” with hydrogen.
  • Monounsaturated fatty acids have one C=C double bond.
  • Polyunsaturated fatty acids have two or more C=C double bonds.

Double bonds and melting point

Saturated chains are straight and pack tightly, so many weak attractions form between neighbouring chains and more energy is needed to separate them: they have high melting points. In most natural unsaturated fatty acids each double bond is cis: the two hydrogen atoms on the C=C are on the same side, which puts a bend in the chain. Bent chains pack loosely, so they melt at lower temperatures. In a trans double bond the hydrogen atoms are on opposite sides and the chain stays nearly straight. Trans fatty acids are uncommon in nature; most in food came from partially hydrogenating plant oils.

Fatty acid (18 carbons) C=C bonds Melting point / °C
Stearic acid (saturated) 0 69
Elaidic acid (one trans) 1 about 45
Oleic acid (monounsaturated, cis) 1 about 13
Linoleic acid (polyunsaturated, cis) 2 about −5

Triglycerides rich in unsaturated fatty acids are oils, liquid at 20 °C. Those rich in saturated fatty acids are fats, solid at 20 °C.

Oils in plants, fats in endotherms

An energy store must stay liquid enough to be mobilized. Plants cannot keep their tissues warm, so they store energy as oils, rich in unsaturated fatty acids, which stay liquid even in cold conditions; examples are the oils of sunflower seeds and olives. Endotherms (birds and mammals) keep their body at a constant high temperature, about 37 °C in most mammals and around 40 °C in birds, so they can store fats with more saturated fatty acids, which are soft or liquid at body temperature. Fats like lard and butter are solid at room temperature but not inside the animal.

Triglycerides in adipose tissue

SL & HLSyllabus understandings: B1.1.11

Adipose tissue is made of cells (adipocytes) that each store a large droplet of triglyceride. In mammals it lies mainly under the skin (subcutaneous fat) and around organs such as the kidneys.

Why triglycerides suit long-term energy storage

  • More energy per gram: oxidizing triglyceride releases about 37 kJ g⁻¹, roughly twice the ≈ 17 kJ g⁻¹ of glycogen, because fatty acids contain more C–H bonds and less oxygen.
  • Stored without water: triglycerides are hydrophobic, so they coalesce into droplets containing almost no water. Glycogen is hydrophilic and is stored with roughly 3 g of water for every gram. A glycogen store holding the same energy would be several times heavier, a large cost for an animal that must move, and especially for one that flies.
  • Inert and insoluble: fat droplets have no osmotic effect and do not react with other molecules in the cell.

Glycogen remains useful as a short-term store: it can be hydrolysed to glucose faster, and glucose can be respired anaerobically, whereas fatty acids can only be respired aerobically. So animals store a little glycogen for rapid use and most of their energy as fat for the long term.

Simulation Fat versus glycogen as an energy store

1 · Storing energy: fat or glycogen?

Mass needed to store the chosen amount of energyTriglyceride37 kJ g⁻¹270 gGlycogen (dry)17 kJ g⁻¹588 gGlycogen + wateras stored in cells2.35 kg

triglyceride glycogen water held with glycogen

To store 10,000 kJ you need 270 g of triglyceride, but 588 g of glycogen, which is stored with 1.76 kg of water: 2.35 kg in all, 8.7 times the mass of fat.

Show data table
StoreEnergy per gramMass needed
Triglyceride37 kJ g⁻¹270 g
Glycogen (dry)17 kJ g⁻¹588 g
Glycogen + water4.3 kJ g⁻¹2.35 kg

2 · Fat as a heat insulator

no heat lossas much as with no fat

Heat loss: about 152 W per m² of skin, 73% of the loss with no fat layer.

Try:

Part 1 uses standard energy values. Part 2 is a qualitative model: it shows the direction and rough size of each effect, ignoring blood flow, shivering and fur.

Text description of this simulation

Part 1 has a slider for the amount of energy to store, from 1,000 to 20,000 kJ, and one for the mass of water stored with each gram of glycogen (0 to 4 g, default 3 g). Horizontal bars show the mass needed as triglyceride, which releases about 37 kJ per gram, as dry glycogen, about 17 kJ per gram, and as glycogen together with its water. For 10,000 kJ about 270 g of fat is needed, but about 590 g of glycogen, which is stored with about 1.8 kg of water, 2.35 kg in all. Part 2 is a qualitative model of heat loss from the body core at 37 °C through a layer of fat to the surroundings. Sliders set the thickness of the fat layer (0 to 8 cm) and the temperature of the surroundings, and buttons choose air or water. A thicker fat layer reduces heat loss, and the effect matters most in cold water, which removes heat far faster than air.

Thermal insulation

Fat conducts heat poorly, so a layer of adipose tissue under the skin reduces heat loss from the body. This matters most for endotherms whose body temperature is far above that of their habitat. Blubber, a thick layer of fat in whales and seals, insulates them in polar seas, where the water is close to 0 °C and conducts heat away far faster than air. The thickness of the fat layer reflects habitat: in hot deserts camels store much of their fat in the hump instead of under all their skin, which makes it easier for them to lose heat.

Phospholipids form bilayers

SL & HLSyllabus understandings: B1.1.12

A phospholipid molecule has two very different regions:

  • the phosphate head, which is charged (polar), so it is hydrophilic: it is attracted to water and forms hydrogen bonds with it;
  • the two fatty acid tails, which are non-polar hydrocarbon chains, so they are hydrophobic.

A molecule with both a hydrophilic and a hydrophobic region is amphipathic.

When phospholipids are mixed with water they arrange themselves, without any energy input, into a bilayer: two layers of molecules with the hydrophobic tails pointing inwards, towards each other, and the hydrophilic heads facing outwards into the water on each side. This arrangement keeps the tails away from water and the heads in contact with it. The tails in the middle are held together by hydrophobic interactions, and the bilayer tends to close up into continuous sheets, without free edges.

The phospholipid bilayer is the basis of every biological membrane. Its hydrophobic core is a barrier to ions and polar molecules, which is why cells need membrane proteins to move them. Membrane structure and transport are covered in B2.1 Membranes and membrane transport.

Triglycerides are different: they have no hydrophilic head, so they are not amphipathic and cannot form bilayers. Instead they gather into droplets, as in adipose cells.

Steroids cross membranes

SL & HLSyllabus understandings: B1.1.13

Recognizing a steroid

Steroids are lipids whose molecules are all built on the same skeleton: four fused rings of carbon atoms, three with six carbons and one with five. Steroids differ in the groups attached to this ring system and in the positions of C=C double bonds. To identify a molecule as a steroid from a diagram, look for the four fused rings, arranged as in the figure. Examples include cholesterol (in animal cell membranes) and the sex hormones testosterone, made mainly in the testes, and oestradiol, a form of oestrogen made mainly in the ovaries.

Testosterone and oestradiol: two steroidsSkeletal formulas of two steroid hormones. Both have the same core of four fused rings of carbon atoms: three six-membered rings, labelled A, B and C, and one five-membered ring, D. Testosterone has a double-bonded oxygen on ring A, a carbon–carbon double bond in ring A, methyl groups where rings A and B meet and where rings C and D meet, and an OH group on ring D. Oestradiol has an aromatic ring A with three double bonds and an OH group, one methyl group where rings C and D meet, and an OH group on ring D.ABCDCH₃OHCH₃OTestosteroneABCDCH₃OHHOOestradiol
Testosterone and oestradiol share the steroid ring system: three six-membered rings (A, B, C) and one five-membered ring (D). Each corner is a carbon atom; hydrogen atoms on carbon are not shown.

Passing through the bilayer

A steroid molecule is almost entirely carbon and hydrogen, with only one or two polar –OH or C=O groups, so overall it is non-polar. It can dissolve in the hydrophobic core of the phospholipid bilayer and therefore diffuses straight through membranes, without needing a channel or carrier protein. This is why steroid hormones such as testosterone and oestradiol can leave the cells that make them and enter their target cells. Inside a target cell they bind to receptor proteins in the cytoplasm or nucleus, which then affect which genes are expressed.

Compare this with peptide hormones such as insulin, which are polar or large and cannot cross the bilayer, so they bind to receptors on the outer surface of the plasma membrane.

Must-know definitions

Covalent bond
A bond in which two atoms share a pair of electrons. A carbon atom has four electrons in its outer shell, so it forms up to four covalent bonds, single or double, with other carbon atoms or with atoms of other non-metals such as H, O, N and P.
Condensation reaction
A reaction that joins two molecules by a new covalent bond and releases a molecule of water, made from an –OH taken from one molecule and an –H from the other. Condensation links monomers into polymers.
Hydrolysis
A reaction that breaks a covalent bond by using up a molecule of water. The water is split: its –H joins one product and its –OH the other. Digestion hydrolyses polymers into monomers.
Monosaccharide
A single sugar unit (a monomer) that cannot be hydrolysed into smaller sugars. Pentoses have five carbon atoms (e.g. ribose) and hexoses six (e.g. glucose, fructose); in water they mostly form rings that include one oxygen atom.
α- and β-glucose
Two ring forms of glucose that differ only at carbon 1: in α-glucose the –OH on carbon 1 is below the ring (opposite side to the CH₂OH), in β-glucose it is above (same side as the CH₂OH).
Glycosidic bond
The C–O–C covalent link between two monosaccharides, made by condensation. In a 1,4 bond carbon 1 of one glucose joins carbon 4 of the next; in a 1,6 bond carbon 1 joins carbon 6, making a branch.
Lipid
A substance from living organisms that dissolves readily in non-polar solvents but only sparingly in water, because its molecules are mostly hydrocarbon with few polar groups. Lipids include fats, oils, waxes, phospholipids and steroids.
Triglyceride and ester bond
A triglyceride (a fat or oil) is one glycerol joined to three fatty acids by three ester bonds, each made by a condensation reaction between an –OH of glycerol and the –COOH of a fatty acid, so three water molecules are released.
Saturated and unsaturated fatty acids
A saturated fatty acid has no C=C double bonds in its chain; a monounsaturated one has one; a polyunsaturated one has two or more. More C=C bonds (in the cis form) mean a lower melting point.
Amphipathic
Having both a hydrophilic part and a hydrophobic part in the same molecule. A phospholipid is amphipathic: its phosphate head is hydrophilic and its two fatty acid tails are hydrophobic, so in water phospholipids form bilayers.
Steroid
A lipid whose molecule is built on four fused rings of carbon atoms: three six-membered rings and one five-membered ring. Examples are cholesterol, testosterone and oestradiol.

Common exam mistakes

  • Loses marks Hydrolysis reactions release water.

    Write instead Hydrolysis uses up water: a water molecule is split and its –H and –OH are added to the products. It is condensation that releases water.

  • Loses marks α-glucose and β-glucose differ in the position of the CH₂OH group (or of the ring oxygen).

    Write instead They differ only in the –OH on carbon 1: below the ring in α-glucose, above it in β-glucose. All other groups, the ring oxygen and carbon 6 are in the same places.

  • Loses marks Drawing α-glucose with the –OH on carbon 1 pointing up.

    Write instead In the standard ring drawing (ring O at the top right, carbon 1 on the right, CH₂OH above carbon 5), α-glucose has its carbon-1 –OH pointing down.

  • Loses marks Counting the corners of the ring: fructose has a five-membered ring, so it is a pentose.

    Write instead Count all the carbon atoms, including those outside the ring. Fructose has four carbons in its ring plus two in CH₂OH groups: six in total, so it is a hexose.

  • Loses marks Cellulose is an energy store made of α-glucose.

    Write instead Cellulose is a structural polysaccharide made of β-glucose, forming the walls of plant cells. The plant energy store is starch, made of α-glucose.

  • Loses marks Starch and glycogen are insoluble because they are hydrophobic.

    Write instead They have many hydrophilic –OH groups, but their molecules are so large that they are only sparingly soluble. Being insoluble, they do not draw water into cells by osmosis.

  • Loses marks A triglyceride is a polymer of fatty acids.

    Write instead A triglyceride is made by condensation, but it is not a polymer: it is one glycerol plus three fatty acids, not a long chain of repeating monomers.

  • Loses marks Fat stores about twice as much energy per gram as glycogen, so a glycogen store would only be twice as heavy.

    Write instead Per gram of dry substance fat releases about twice the energy (≈ 37 vs ≈ 17 kJ g⁻¹), but glycogen is stored with roughly 3 g of water per gram, so a glycogen store holding the same energy is several times heavier.

  • Loses marks A saturated fatty acid is one that is full of fat.

    Write instead Saturated means saturated with hydrogen: all the carbon–carbon bonds are single, so no more hydrogen atoms could be added to the chain.

  • Loses marks Steroid hormones enter cells through channel proteins or by active transport.

    Write instead Steroids such as oestradiol and testosterone are non-polar, so they dissolve in the hydrophobic core of the bilayer and diffuse straight through it, without membrane proteins.

Self-test

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Multiple-choice questions

  1. Question 1A cellulose microfibril in a plant cell wall is about 3 nm wide. What is this width in micrometres (μm)?
  2. Question 2An unbranched amylose molecule contains 500 α-glucose units. How many water molecules were released when it was built from free glucose by condensation?
  3. Question 3Which statement correctly describes the role of water in the hydrolysis of maltose into two glucose molecules?
  4. Question 4A molecular diagram shows a sugar with a five-membered ring made of four carbon atoms and one oxygen atom. Two of the ring carbons each carry a CH₂OH group (one of these two also carries an –OH), and the other two ring carbons each carry an –OH and an –H. How should this monosaccharide be classified?
  5. Question 5In what way does a molecule of β-glucose differ from a molecule of α-glucose?
  6. Question 6Glycogen in liver and muscle cells is more highly branched than amylopectin in plants. What is the main advantage of this extra branching for an animal?
  7. Question 7Why can cellulose molecules form strong microfibrils whereas amylose molecules cannot?
  8. Question 8A person has blood group A. Which statement describes the carbohydrate chains on the glycoproteins of their red blood cells?
  9. Question 9The melting points of three fatty acids, each with 18 carbon atoms, are stearic acid (no C=C bonds) 69 °C, oleic acid (one cis C=C bond) 13 °C and linoleic acid (two cis C=C bonds) −5 °C. Which conclusion is best supported by these data?
  10. Question 10A migrating bird needs to store 2,000 kJ of energy. Fat releases 37 kJ g⁻¹ and glycogen 17 kJ g⁻¹, and each gram of glycogen is stored with about 3 g of water. About how many times heavier would a glycogen store (including its water) be than a fat store?

Flashcards

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Prompt

Why can carbon form such a diversity of compounds?

Last reviewed 19 October 2026. Spotted a mistake? Report it.

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