C4.1 Populations and communities

SL & HLSL and HL · Ecosystems · Theme C

Big questions

  • What keeps a population from growing forever?
  • How do different species in a community depend on, compete with and limit each other?

Populations and estimating their size

SL & HLSyllabus understandings: C4.1.1 · C4.1.2 · C4.1.3

A population is a group of organisms of the same species living in the same area and interacting. Members of a population normally interbreed with each other. A species may consist of one population or many: populations of the same species are separated by reproductive isolation, most often a geographical barrier such as a mountain range or the sea between two islands, so individuals breed mostly within their own population.

Why we estimate rather than count

The population size is the total number of individuals. Counting every one is usually impossible: the population may be spread over a large area, the organisms may be small, hidden or camouflaged, animals move around, and counting can damage the habitat. Instead, we count a sample and scale up to an estimate.

  • The sample must be random: every individual (or every part of the habitat) must have an equal chance of being sampled. Choosing “typical-looking” spots introduces bias. Random numbers from a table, calculator or app are used to pick sample positions.
  • Any estimate based on a sample differs from the true value. This difference is the sampling error. More samples reduce it, but it can never be eliminated without counting everyone.

Random quadrat sampling

Quadrats are square frames of known area (for example 1 m × 1 m, or 0.5 m × 0.5 m = 0.25 m²). They suit sessile organisms, which stay in one place: plants such as daisies or dandelions, and sessile animals such as barnacles and mussels on rocky shores.

  1. Mark out the site and measure its area. Lay two measuring tapes at right angles along two edges as axes.
  2. Generate pairs of random coordinates and place a quadrat at each.
  3. Count the individuals rooted or attached inside each quadrat.
  4. Calculate the mean number per quadrat, then: population estimate = mean per quadrat × total area ÷ area of one quadrat.
Simulation Random quadrat sampling
A 20 m × 20 m field of plants with sample quadratsEach dot is one plant. Squares are 1 m × 1 m quadrats placed at random coordinates; the most recent one is highlighted. Faint lines are every 5 m.

Field 20 m × 20 m = 400 m²; quadrat 1 m × 1 m

Distribution:

No quadrats placed yet. Each quadrat is placed at random coordinates, and the plants rooted inside it are counted.

Population estimate after each quadrat; the line settles down as more quadrats are sampled0102030405002505007501000Number of quadrats sampledEstimatePlace quadrats to build up an estimate
Show data table
Quadratx / my / mPlants counted
No quadrats yet

Simulated field. Coordinates are random numbers to 0.1 m, so every part of the field has an equal chance of being sampled. A plant counts if it is rooted inside the quadrat. The standard deviation is calculated as on a calculator (n − 1).

Text description of this simulation

A square field 20 m by 20 m in which each dot is one plant. The plants can be spread at random, in clumps or evenly. Each button press places quadrats measuring 1 m by 1 m at random coordinates and counts the plants inside. The panel shows the number of quadrats, the mean count per quadrat, its standard deviation and the population estimate (mean per quadrat × 400 m² ÷ 1 m²). A graph below plots the estimate after each quadrat: it swings widely at first and settles as more quadrats are added. The true population can be revealed to show the sampling error. Clumped plants give a standard deviation larger than the mean and a less reliable estimate; evenly spread plants give a small standard deviation.

Standard deviation of the counts

Use a calculator to find the standard deviation (SD) of the counts per quadrat; you do not need to learn the formula. SD measures the spread of the counts around the mean. To judge whether the spread is large, compare it with the mean (or with other sites):

  • If the organisms are scattered at random, the variance (SD²) is roughly equal to the mean, so variance ÷ mean ≈ 1.
  • Large SD: variance well above the mean (variance ÷ mean above about 1.5) suggests the organisms are clumped. A large SD relative to other sites with a similar mean shows clumping too. A few quadrats can swing the estimate, so more quadrats are needed.
  • Small SD: variance well below the mean (variance ÷ mean below about 0.67) suggests the organisms are evenly spread. A small SD relative to other sites with a similar mean shows even spacing, and the estimate is more reliable.

Capture–mark–release–recapture

SL & HLSyllabus understandings: C4.1.4

Motile animals move between samples, so quadrats do not work for them. Instead, capture–mark–release–recapture is used, for example with snails, woodlice, ground beetles or small mammals.

  1. Capture as many individuals as possible in the area using nets, traps or careful searching. Count them: this is M.
  2. Mark each one harmlessly, for example a dot of non-toxic paint on the underside of a snail shell, where it does not make the snail more visible to birds.
  3. Release them where they were caught and leave time for them to mix back into the population.
  4. Capture a second sample. Count the total caught (N) and how many of these carry a mark (R).
  5. Use the Lincoln index: population estimate = M × N ÷ R.

The logic is that the proportion of marked animals in the second sample (R/N) should equal the proportion of the whole population that was marked (M/population).

Worked example. 60 ground beetles are caught and marked. A week later 45 are caught, of which 9 are marked. Estimate = 60 × 45 ÷ 9 = 300 beetles.

Simulation Capture–mark–release–recapture and the Lincoln index
Population estimate = M × NR
  • M = number caught and marked in the first sample
  • N = total number caught in the second sample
  • R = number of marked individuals in the second sample
The animals in the habitat at the time of the second sampleGrey dots are unmarked animals, red dots are marked animals, and a thick dark ring shows an animal caught in the second sample. Hollow red rings are animals whose marks have worn off.
Break an assumption

Press “Run a survey” to catch and mark a first sample, release it, then take a second sample.

Dot plot of the estimates from repeated surveys, with the true population size marked0150300450600750+Population estimate from each surveytrue sizeRepeated surveys appear here

No repeated surveys yet. A triangle under the axis will mark the mean estimate.

Simulated animals. Each survey uses new random samples, so estimates vary even when every assumption holds; the mean of many surveys is close to the true size. Changing a slider or an assumption clears the results.

Text description of this simulation

A habitat containing a population of motile animals. A survey catches and marks a first sample (M), releases it, then catches a second sample (N) and counts how many of those are marked (R). The estimate M × N ÷ R is compared with the true population size. Sliders set the true size and the two sample sizes. Checkboxes break each assumption of the method: marks wearing off, marked animals being eaten more often, marked animals not mixing back into the population, and unmarked animals migrating in. A dot plot collects the estimates from repeated surveys so you can see how much they vary and whether they are too high or too low.

Assumptions

The estimate is valid only if, between the two samples:

  • the population is closed: no births, deaths, immigration or emigration;
  • marks are not lost and remain visible;
  • marking does not affect survival or behaviour (for example, does not make animals easier for predators to spot);
  • marked animals mix randomly back into the population, so every individual has the same chance of being caught in the second sample.

If marks wear off or marked animals die, R is too small and the population is overestimated. If marked animals stay near the trap, or become “trap-happy”, R is too large and the population is underestimated.

Carrying capacity and negative feedback

SL & HLSyllabus understandings: C4.1.5 · C4.1.6

Every population depends on resources that are in limited supply. If a population grows, there are more individuals sharing the same resources, so they compete. The carrying capacity (K) is the maximum population size that an environment can support. Usually one resource, the one in shortest supply, sets it.

Organisms Resources that can limit carrying capacity
Plants light, water, mineral ions in the soil (such as nitrate and phosphate), space to grow
Animals food, water, territories or nest sites for breeding, shelter, dissolved oxygen (for aquatic animals)

Density-dependent and density-independent factors

Density-independent factors affect a population whatever its density. A flood, a forest fire or a hard frost may kill a large proportion of a population, but roughly the same proportion whether the population is sparse or crowded. They make numbers fluctuate.

Density-dependent factors have stronger effects in denser populations, so they push numbers back towards K:

  • Competition for limited resources: in a crowded population each individual gets less food, water or space, so fewer survive or breed.
  • Predation: predators find prey more easily, and more predators can be supported, when prey are abundant.
  • Pathogens and pests spread more easily between individuals living close together.

This is negative feedback. Above K, birth rate falls and death rate rises, so numbers fall; below K, competition, predation and disease ease, so numbers rise.

Negative feedback keeps a population near its carrying capacityAt the top, a population at carrying capacity K. On the left, if it rises above K, competition, predation and disease increase, the birth rate falls and the death rate rises, so numbers fall back towards K. On the right, if it falls below K, these factors weaken, the birth rate rises and the death rate falls, so numbers rise back towards K. A note at the bottom says density-independent factors such as floods or frost can change numbers whatever the density.Population at itscarrying capacity (K)Population risesabove KMore competition forresources; predators anddisease spread more easilyBirth rate falls,death rate risesPopulation fallsbelow KLess competition;predation and diseasehave less effectBirth rate rises,death rate fallsnumbers return towards KDensity-independent factors (floods, fire, a hard frost) change numberswhatever the density, so populations fluctuate around K.
Density-dependent factors act as negative feedback, returning a population towards its carrying capacity after it rises above or falls below it.

Population growth curves

SL & HLSyllabus understandings: C4.1.7 · C4.1.8

When a few individuals colonize a new, favourable habitat, the population usually grows in an S-shaped or sigmoid curve. This curve is an idealized model: a simplification that helps us understand real populations, which rarely fit it exactly.

The phases of sigmoid population growth
exponentialtransitionalplateauKTime →Population size →a few foundersbirths far exceed deathsgrowth slows:density-dependent factorsbirths = deathsfrost kills 45%(density-independent)Per-capitaratesbirthsdeaths
Text description of this animation

A graph of population size against time builds up step by step into an S-shaped (sigmoid) curve that levels off at the carrying capacity K, shown as a dashed line. Beside it, two bars show the per-capita birth rate and death rate. The birth bar starts high and the death bar low; as the population grows, density-dependent factors make births fall and deaths rise until the bars are equal at K. In the last step a hard frost kills almost half of the population, and it grows back to K.

  1. A few founders arrive. A small number of individuals colonize a new habitat, for example duckweed in a pond or yeast in fresh medium. Resources are plentiful and there is little competition. There is no lag phase in the model; growth starts at once.
  2. Exponential phase. Births far exceed deaths. The per-capita growth rate is almost constant while numbers are far below K, so each generation adds more individuals than the one before and the curve gets steeper. Numbers would double in equal times if this continued.
  3. Transitional phase. Density-dependent factors start to act. Competition for food, space or light increases, predators find prey more easily and pathogens spread faster. The birth rate falls and the death rate rises, so the curve becomes less steep after its steepest point at K/2.
  4. Plateau at the carrying capacity. The population has reached the carrying capacity (K), the maximum the environment can support. The birth rate equals the death rate, so numbers stay roughly constant.
  5. Negative feedback after a disturbance. A density-independent event, such as a hard frost, kills 45% of the population regardless of density. With fewer individuals, competition, predation and disease ease, births exceed deaths again and the population returns to K. This is negative feedback.
  • Exponential phase. Resources are abundant and there is little competition, predation or disease, so births greatly exceed deaths. Each individual produces offspring at a constant rate, so the more individuals there are, the faster the population grows. The model has no lag phase: growth is exponential from the start.
  • Transitional phase. As numbers rise, density-dependent factors take effect. The birth rate falls and/or the death rate rises. The population still grows, but more slowly.
  • Plateau phase. The population reaches the carrying capacity. Births equal deaths, and numbers stay roughly constant, fluctuating around K.

Case study: reindeer on St Matthew Island

In 1944, 29 reindeer were released on St Matthew Island in the Bering Sea, Alaska. The island had thick mats of lichen (their winter food) and no predators. Counts rose to about 1350 in 1957 and about 6000 in 1963, then the population crashed to 42 by 1966 after the lichen had been overgrazed and a very severe winter struck. The early growth was exponential because food was plentiful and there was nothing to kill the reindeer; the population then overshot the carrying capacity, so this case did not level off in a plateau.

Testing for exponential growth with a log scale

To test whether growth was exponential, plot population size on a logarithmic vertical axis against time on a normal (linear) axis. Exponential growth multiplies numbers by the same factor in each equal time interval, so on a log scale it gives a straight line. If the points lie close to a straight line, growth was close to exponential; if they curve downwards, growth was slowing.

Reindeer on St Matthew Island, plotted on linear and logarithmic axesCounts: 29 reindeer introduced in 1944, about 1350 in 1957, about 6000 in 1963, and 42 in 1966 after a crash. On the linear axis the rise curves upwards steeply. On the logarithmic axis the points from 1944 to 1963 lie close to a straight line, which is the sign of exponential growth; then numbers crash.Linear scale02,0004,0006,0001940195019601970YearLog scale1101001,00010,0001940195019601970Yearcrash≈ straight line
St Matthew Island reindeer counts (Klein, 1968). On a log scale the counts from 1944 to 1963 lie close to a straight line, showing near-exponential growth, before the crash.

Modelling the sigmoid curve: duckweed and yeast

Organisms that multiply quickly in the laboratory let you collect your own growth data:

  • Duckweed (Lemna) floats on water. Put a few plants in beakers of water containing mineral ions, in bright light and warmth, and count the fronds every two days for several weeks. Space on the water surface or mineral ions eventually limit growth.
  • Yeast (Saccharomyces) can be grown in sugar solution and counted under the microscope with a haemocytometer, or estimated from the cloudiness of the culture. Sugar runs out and ethanol builds up, so numbers level off (and later fall).

Use several replicate beakers so the reliability of the results can be judged, and plot mean numbers against time.

Simulation Modelling population growth
Population size against time: exponential and sigmoid (logistic) modelsThe exponential curve keeps getting steeper. The sigmoid curve rises steeply at first, then levels off at the carrying capacity K. Shaded bands mark the exponential, transitional and plateau phases.exponentialtransitionalplateauK = 3200510152025300100200300400500600700Time / daysNumber of fronds
Show

Day 6: the sigmoid (logistic) model predicts 61 fronds; the exponential model predicts 73. Exponential phase: resources are plentiful and there are few individuals to compete, so births far exceed deaths. The more individuals there are, the faster numbers rise. Fit to the duckweed data: the model is off by about 6 fronds on average (root-mean-square).

Show data table
DayFronds countedSigmoid modelExponential model
0121212
2202122
4353740
6656173
89896132
10141140241
12186188439
14230231800
162562641458
182892872657
203093014841
223003098821
2430131416073
2632731729287

Idealized models: real populations rarely follow either curve exactly. The duckweed counts are illustrative values of the kind a class investigation produces (12 fronds in a beaker of mineral-ion solution, counted every two days), not published data. Phase boundaries are drawn at 25% and 95% of K; the change from one phase to the next is gradual.

Text description of this simulation

A graph of number of duckweed fronds against time in days. The exponential model (dashed) rises ever more steeply. The sigmoid (logistic) model (solid) follows it at first, then slows and levels off at the carrying capacity K. Shaded bands mark the exponential, transitional and plateau phases. Sliders set the growth rate r and K, and a button finds the values that best fit the illustrative duckweed counts. A checkbox switches the vertical axis to a logarithmic scale, on which exponential growth is a straight line and the sigmoid curve and the data bend away from it as they approach K.

Relationships within and between species

SL & HLSyllabus understandings: C4.1.9 · C4.1.10 · C4.1.11

Intraspecific competition and cooperation

Members of the same species have the same requirements: the same food, the same nest sites, the same mates. When a resource is limited, they compete (intraspecific competition). Examples:

  • Trees and other plants of the same species growing close together compete for light, water and mineral ions; many seedlings die, and the survivors are spaced out (self-thinning).
  • European robins defend territories in which they feed and breed; birds without a territory usually do not breed.
  • Red deer stags compete, by roaring and fighting, for access to females in the breeding season.

Members of a population also cooperate when working together raises the survival or reproduction of each:

  • Honeybee workers share the tasks of foraging, nursing larvae and defending the hive.
  • Meerkats take turns as sentinels, watching for predators while others feed.
  • Emperor penguins huddle in large groups through the Antarctic winter, reducing heat loss.
  • Wolves hunt in packs, so they can kill prey much larger than a single wolf.

Communities

A community is all the interacting populations of the different species in an area: plants, animals, fungi, bacteria and other microorganisms. No population lives in isolation; each depends on others for food, pollination, nutrient cycling or shelter.

Interspecific relationships

Relationship Effect on each species Example
Herbivory herbivore benefits; plant is harmed (but usually not killed) snowshoe hares browsing willow and birch twigs in winter
Predation predator benefits; prey is killed and eaten Canada lynx hunting snowshoe hares
Interspecific competition both are harmed, as they use the same limited resource lions and spotted hyenas competing for the same prey
Mutualism both benefit Rhizobium bacteria in legume root nodules
Parasitism parasite benefits; host is harmed, usually without being killed quickly ticks feeding on the blood of deer
Pathogenicity pathogen benefits; host develops a disease chytrid fungus (Batrachochytrium dendrobatidis) infecting the skin of frogs

Mutualism and invasive species

SL & HLSyllabus understandings: C4.1.12 · C4.1.13

Three mutualisms

Root nodules in Fabaceae (legumes). Peas, beans, clover and other legumes form root nodules containing Rhizobium bacteria. The bacteria fix nitrogen: they convert N₂ from the air into ammonium (NH₄⁺), which the plant uses to make amino acids, so legumes thrive in nitrogen-poor soil. The plant supplies the bacteria with carbon compounds from photosynthesis, for respiration, and a protected, low-oxygen environment (oxygen would inactivate the enzyme that fixes nitrogen).

Mycorrhizae in Orchidaceae (orchids). Fungal hyphae grow into the roots of orchids, entering root cells (through the cell wall, but not the plasma membrane) and forming coils. The hyphae also spread far through the soil and act as an extension of the root system, absorbing water and mineral ions (such as phosphate) and passing them to the orchid. Orchid seeds are tiny, with almost no food reserves, so seedlings depend on the fungus for sugars as well. Adult green orchids can pass some photosynthetic sugars to the fungus (shown in some species).

Zooxanthellae in hard corals. Reef-building hard corals have single-celled photosynthetic algae (dinoflagellates called zooxanthellae) living inside their cells. The algae pass most of the sugars and other organic compounds (such as amino acids) they make by photosynthesis, and oxygen, to the coral. The coral provides the algae with CO₂ from its respiration, nitrogen and phosphorus compounds from its wastes, and a protected position in the light. When corals are stressed by high temperatures, they expel the algae and lose their colour (bleaching).

Three mutualisms and what each partner gainsRow 1: a legume plant gives Rhizobium bacteria in its root nodules sugars and a low-oxygen environment; the bacteria fix nitrogen gas and give the plant ammonium. Row 2: a mycorrhizal fungus gives an orchid water and mineral ions, and gives seedlings sugars; adult green orchids can pass some photosynthetic sugars to the fungus (shown in some species). Row 3: a hard coral gives its zooxanthellae carbon dioxide, nitrogen and phosphate compounds and a sheltered, well-lit home; the zooxanthellae give the coral sugars, amino acids and oxygen from photosynthesis.Legume plant(Fabaceae, e.g.pea, clover)Rhizobiumbacteria inroot nodulessugars and other carboncompounds; a low-O₂ homeammonium (NH₄⁺) madeby fixing N₂ from the airOrchid(Orchidaceae)Mycorrhizalfungus: hyphaein root cellssome photosynthetic sugars(adult green orchids; some species)water and mineral ions;sugars for seedlingsHard coralpolypZooxanthellae(photosyntheticalgae in its cells)CO₂, nitrogen and phosphatefrom its wastes; shelter in lightsugars, amino acids andO₂ from photosynthesis
What each partner gains in the three mutualisms you need to know.

Invasive species and endemic species

Endemic (native) species occur naturally in an area. Alien species have been introduced by humans, deliberately or by accident. An alien species becomes invasive when it spreads rapidly, often because its own predators, parasites and diseases were left behind, and it outcompetes endemic species for resources. Endemic species with an overlapping niche may decline or be excluded.

Testing for interspecific competition

SL & HLSyllabus understandings: C4.1.14 · C4.1.15

If one species does better when another species is absent, interspecific competition is indicated, but not proven: the two might simply prefer different conditions. Hypotheses about competition can be tested in several ways:

  • Laboratory experiments. Grow the species separately and together under controlled conditions. Gause grew two species of Paramecium on the same food: each thrived alone, but together one species outcompeted and eliminated the other.
  • Field manipulation (removal experiments). Remove one species from some areas and compare with control areas. On a Scottish rocky shore, Connell removed the barnacle Balanus (Semibalanus) from rocks, and the barnacle Chthamalus then survived lower on the shore than usual.
  • Field observations by random sampling. Record the presence or absence of each species in random quadrats and test whether they occur together more or less often than chance predicts (the chi-squared test below).

Experiments and observations. In an experiment the scientist intervenes, changing one variable and controlling others. In an observational study the scientist records what happens naturally without changing anything. Both can test hypotheses, but observations show only correlation; manipulation gives stronger evidence of cause.

The chi-squared test for association

  1. State hypotheses. H₀: the two species are distributed independently. H₁: the species are associated.
  2. Record presence/absence in many random quadrats in a 2 × 2 contingency table of observed frequencies (O), with row and column totals.
  3. Calculate each expected frequency: E = row total × column total ÷ grand total.
  4. Calculate χ² = Σ (O − E)² ÷ E.
  5. Degrees of freedom = (rows − 1)(columns − 1) = 1. The critical value at p = 0.05 is 3.84.
  6. If χ² > 3.84, reject H₀: there is a significant association. Compare O with E for “both present” to find its direction.

Worked example. In 50 quadrats, species A is present in 25 and species B in 23, but they occur together in only 6. Expected (both) = 23 × 25 ÷ 50 = 11.5. The four expected values are 11.5, 11.5, 13.5 and 13.5, and χ² = 9.74 > 3.84. The species are negatively associated (found together less often than expected), which may be due to competition or to different habitat requirements.

Simulation Chi-squared test for association between two species
50 quadrats, showing which contain species A (circle) and species B (square)BABBABBBABBBABABAAAAAABABBBABABAABAAABAABABAAABB

Each square is one quadrat placed at random. A = species A present; B = species B present.

Observed frequencies (O): type to change them
A presentA absentRow total
B present23
B absent27
Column total252550
Expected frequencies (E) = row total × column total ÷ grand total
A presentA absentRow total
B present11.5011.5023
B absent13.5013.5027
Column total252550
(O − E)² ÷ E2.63 + 2.63 + 2.24 + 2.24

χ² = 9.74, degrees of freedom = (2 − 1)(2 − 1) = 1, critical value at p = 0.05 = 3.84. 9.74 > 3.84, so the null hypothesis is rejected (p < 0.05). The species occur together in 6 quadrats, fewer than the 11.5 expected: a negative association. This is consistent with interspecific competition, but the species might simply need different habitats.

H₀: the two species are distributed independently of each other. H₁: the species are associated. The surveys are simulated: in “competing species” B is less likely to be in a quadrat that contains A, and in “shared habitat” more likely. By chance, about 1 survey in 20 of non-interacting species still gives a significant result at p = 0.05.

Text description of this simulation

A grid of quadrats shows which contain species A, species B, both or neither. The observed frequencies are entered in a 2 × 2 contingency table, which can be edited. Expected frequencies are calculated as row total × column total ÷ grand total, then each (O − E)² ÷ E and their sum, χ². With one degree of freedom the critical value at p = 0.05 is 3.84. The conclusion states whether the null hypothesis of independent distribution is rejected and whether any association is positive or negative. Buttons load a worked example and simulated surveys of non-interacting species, competing species and species that share a habitat.

Predator–prey cycles and control of populations

SL & HLSyllabus understandings: C4.1.16 · C4.1.17

Predation is a density-dependent factor, and in many communities predator and prey populations regulate each other. Four linked effects can produce cycles:

  1. More prey → more food for predators → predators survive and breed better → predator numbers rise.
  2. More predators → more prey eaten → prey numbers fall.
  3. Fewer prey → predators starve or fail to breed → predator numbers fall.
  4. Fewer predators → fewer prey eaten → prey numbers recover.

Case study: Canada lynx and snowshoe hare

In the boreal forests of Canada, numbers of snowshoe hares rise and fall in cycles lasting about 10 years, and numbers of Canada lynx, which depend heavily on hares for food, follow with a delay of one or two years. The evidence comes from the numbers of pelts traded by trappers to the Hudson’s Bay Company over more than 100 years, and from later field counts. Field experiments in the Yukon showed that hares are limited by both predators and winter food: excluding predators or adding food each raised hare numbers, and doing both raised them far more.

Simulation Predator–prey cycles (lynx and snowshoe hare model)
Model numbers of snowshoe hares and Canada lynx over 60 yearsHares on the left axis (solid line) and lynx on the right axis (dashed line). In the classic model both rise and fall in repeated cycles, with lynx peaks following hare peaks.0102030405060010020030040020406080Time / yearsHares (prey) →Lynx (predators) →

Hare numbers peak about every 11.4 years, and each lynx peak follows a hare peak by about 1.8 years. More hares → more food for lynx → more lynx → more hares eaten → fewer hares → lynx starve → fewer lynx → hares recover. With unlimited food, the classic model cycles for ever: hares are controlled top-down, by predation.

Show data table
YearHaresLynx
06015
104526
205246
3011469
4030752
5032618
6020110

Qualitative model (Lotka–Volterra, with an optional food limit for the hares), in arbitrary units. Real hare–lynx cycles last about 10 years, but they are also driven by the hares' winter food, by other predators and by the weather, so real data are far less regular than this.

Text description of this simulation

A Lotka–Volterra model of snowshoe hares (prey, solid line, left axis) and Canada lynx (predators, dashed line, right axis) over 60 years. In the classic model both populations rise and fall in repeated cycles, with each lynx peak coming after a hare peak. A food slider limits the hares' carrying capacity (bottom-up control): limited food damps the cycles to a steady state, and very little food means the lynx die out. A hunting-success slider changes how strongly lynx limit hares (top-down control). Removing the lynx lets hares grow until food limits them.

Top-down and bottom-up control

  • Top-down control: a population is limited by organisms at the trophic level above it (its predators or herbivores). Example: sea otters eat sea urchins; where otters are present, urchins are kept scarce and kelp forests flourish, but where otters were hunted out, urchins multiplied and grazed the kelp away.
  • Bottom-up control: a population is limited by the trophic level below it, ultimately by resources such as mineral nutrients. Example: in many lakes the supply of phosphate limits phytoplankton, which in turn limits the zooplankton and fish that depend on them.

Both kinds of control operate in most communities, but one is usually dominant in a particular community.

Bottom-up and top-down control in two example communitiesLeft, bottom-up control in a lake: the supply of nitrate and phosphate limits phytoplankton, which limits zooplankton, which limits fish; arrows point upwards. Right, top-down control in a kelp forest: sea otters limit sea urchins by eating them, so the urchins cannot overgraze the kelp; arrows point downwards.Bottom-up (a lake)Top-down (a kelp forest)Fishsecondary consumerslimitsZooplanktonprimary consumerslimitsPhytoplanktonproducerslimitsNitrate and phosphatemineral nutrientsSea otterspredatorseat, so limitSea urchinsherbivoresgraze, so limitKelpproducersRemove the otters: urchins multiplyand graze the kelp forest away.Add phosphate: every level can grow.
Bottom-up control in a lake (resources limit each level from below) and top-down control in a kelp forest (sea otters limit sea urchins, which protects the kelp).

Allelopathy and antibiotics

SL & HLSyllabus understandings: C4.1.18

Some organisms reduce competition chemically: they release substances into the environment that harm or deter potential competitors. Both allelopathic chemicals and antibiotics are secondary metabolites, made by pathways found only in certain groups of organisms and not needed for basic growth.

Allelopathy

Allelopathy is the release of chemicals by a plant, through its roots, leaves or decaying litter, that inhibit the germination or growth of other plants nearby, so the plant faces less competition for water, light and mineral ions.

Example: black walnut (Juglans nigra). Its roots, leaves and nut husks contain a compound that is converted in the soil into juglone, which inhibits the growth of many other plants, such as tomatoes and apple trees, under and around the tree.

Antibiotic secretion

Antibiotics are chemicals secreted by microorganisms that kill or inhibit the growth of other microorganisms, especially bacteria, competing for the same food.

Example: Streptomyces bacteria in soil secrete many antibiotics, including streptomycin (from Streptomyces griseus), which inhibit other soil bacteria. Similarly, the fungus Penicillium secretes penicillin, which stops bacteria building their cell walls, reducing competition for the nutrients the fungus is digesting.

Must-know definitions

Population
A group of organisms of the same species living in the same area at the same time, which normally interbreed. Populations of one species are separated by reproductive isolation, often a geographical barrier.
Community
All the populations of all the different species living and interacting in an area, including plants, animals, fungi and bacteria.
Sampling error
The difference between an estimate of population size made by sampling and the true size of the whole population. Random sampling with more samples reduces it but cannot remove it.
Lincoln index
Estimate of a motile population by capture–mark–release–recapture: population = M × N ÷ R, where M = number marked in the first sample, N = total caught in the second sample, R = marked individuals in the second sample.
Carrying capacity (K)
The maximum population size of a species that an environment can support indefinitely, set by the supply of whichever resource is limiting (such as food, water, light, mineral ions or nest sites).
Density-dependent factor
A factor whose effect on birth or death rate gets stronger as the population becomes more crowded: competition for resources, predation and the spread of pathogens and pests. These factors give negative feedback towards K.
Sigmoid population growth
S-shaped growth: an exponential phase (resources plentiful), a transitional phase (density-dependent factors slow growth) and a plateau at the carrying capacity, where births equal deaths.
Mutualism
A close interspecific relationship in which both species benefit, for example legumes and Rhizobium in root nodules, orchids and mycorrhizal fungi, hard corals and zooxanthellae.
Invasive species
An alien species, introduced by humans to a region outside its native range, that spreads and becomes abundant, usually by outcompeting endemic species for resources.
Chi-squared test for association
A statistical test of whether two species are distributed independently, using a 2 × 2 table of presence/absence in quadrats. df = 1, so if χ² > 3.84 the association is significant at p = 0.05.
Allelopathy
The release by a plant of chemicals into the environment (usually the soil) that inhibit the germination or growth of other plants, reducing competition. Secretion of antibiotics by microorganisms works in the same way.

Common exam mistakes

  • Loses marks Lincoln index: population = M × R ÷ N (or forgetting which sample N refers to).

    Write instead Population = M × N ÷ R. M is the number marked in the first sample, N is the total caught in the second sample, and R is the number of those that were already marked.

  • Loses marks Population estimate from quadrats = mean number per quadrat × total area.

    Write instead Divide by the area of one quadrat as well: estimate = mean per quadrat × total area ÷ quadrat area. The two give the same answer only for a 1 m² quadrat with the area in m².

  • Loses marks A large standard deviation means the quadrat counts were added up wrongly.

    Write instead Standard deviation measures spread. A large one (relative to the mean, or to other sites with a similar mean) shows the counts varied a lot between quadrats, usually because the organisms are clumped, so the estimate is less reliable.

  • Loses marks Sigmoid growth begins with a lag phase.

    Write instead In the IB population model there is no lag phase: growth is exponential from the start, when resources are plentiful. (Lag phases belong to microbial cultures adjusting to new medium.)

  • Loses marks At the plateau, organisms stop reproducing.

    Write instead At the carrying capacity births continue, but the birth rate equals the death rate, so the population size stays roughly constant.

  • Loses marks A flood or hard frost is a density-dependent factor because it kills many individuals.

    Write instead Weather events kill a similar proportion whatever the population density, so they are density-independent. Density-dependent factors (competition, predation, disease) act more strongly in crowded populations.

  • Loses marks A significant chi-squared result proves the two species compete.

    Write instead It shows only an association. A negative association is consistent with competition but could be due to different habitat requirements. A removal experiment or a laboratory experiment can test competition more directly.

  • Loses marks In mutualism, Rhizobium gives the legume nitrogen gas.

    Write instead The plant cannot use N₂. Rhizobium fixes N₂ into ammonium (NH₄⁺), which the plant uses to make amino acids; in return the plant supplies carbon compounds from photosynthesis.

  • Loses marks Predator and prey numbers peak at the same time.

    Write instead Predator peaks lag behind prey peaks: predators increase only after prey are abundant, and prey decline only after predators have become numerous.

Self-test

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Multiple-choice questions

  1. Question 1To estimate a population of woodlice, 40 were caught, marked and released. Two days later 50 woodlice were caught, of which 8 were marked. What is the estimated population size?
  2. Question 2In a capture–mark–release–recapture study of snails, the paint used to mark the shells washed off some snails before the second sample was taken. How will this affect the population estimate?
  3. Question 3Ten quadrats, each 0.25 m², were placed at random in a meadow with an area of 50 m². The mean number of dandelions per quadrat was 3.2. What is the estimated number of dandelions in the meadow?
  4. Question 4Two populations were sampled with 20 random quadrats each. Population X had a mean of 4.0 plants per quadrat (standard deviation 0.8); population Y had a mean of 4.0 (standard deviation 5.1). What can be concluded?
  5. Question 5Which of these is a density-independent factor affecting a population of field mice?
  6. Question 6A student plots the number of yeast cells (on a logarithmic vertical axis) against time (on a linear horizontal axis). For the first 8 hours the points lie on a straight line rising from left to right. What does this show?
  7. Question 7In the mutualism between a legume plant and Rhizobium bacteria, what does each partner receive?
  8. Question 8In 60 random quadrats, species A was present in 30, species B in 20, and both together in 4. What is the expected number of quadrats containing both species if they are distributed independently, and what does the observed number suggest?
  9. Question 9Ecologists removed all plants of one grass species from some plots in a meadow and left control plots untouched. A year later a second grass species had increased in the removal plots only. Which statement is correct?
  10. Question 10Records of snowshoe hares and Canada lynx show cycles of about 10 years, with lynx numbers peaking one to two years after hare numbers. What is the best explanation for this delay?

Flashcards

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Prompt

What is a population, and what separates one population of a species from another?

Last reviewed 19 October 2026. Spotted a mistake? Report it.

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