D1.1 DNA replication

SL & HL+ AHL sectionsSL and HL, with AHL content · Molecules · Theme D

Big questions

  • How does a cell make a faithful copy of its entire genome?
  • How have scientists turned the copying of DNA into tools for medicine and forensics?

Sections framed in purple are AHL (Higher Level only). SL students can hide them in Display settings.

Replication makes exact copies of DNA

SL & HLSyllabus understandings: D1.1.1

DNA replication is the production of new DNA molecules with exactly the same base sequence as the original. A cell replicates all of its DNA before it divides, so that each daughter cell receives a complete copy of the genome. (In eukaryotes this happens during the S phase of interphase.)

Cell division, and therefore replication, is needed for:

  • Reproduction: unicellular organisms reproduce by cell division, and multicellular organisms use cell division to produce the cells that become gametes. Base sequences are passed from generation to generation.
  • Growth: a multicellular organism grows by producing more cells, each with the same genome.
  • Tissue replacement: cells lost through damage or wear, such as skin and gut lining cells, are replaced by division of other cells.

Because the copies are so accurate, the genetic information in every body cell is (almost) identical, and offspring inherit the same base sequences their parents carried. Replication is a process of continuity rather than change. Rare copying errors are one source of mutations (see D1.3 Mutation and gene editing).

The base sequence carries the information that is transcribed and translated into polypeptides (D1.2 Protein synthesis). Because copies must be faithful, replication has several safeguards built in: the two strands are used as templates, bases pair only in complementary pairs, and (higher level) DNA polymerase checks its own work.

Semi-conservative replication and complementary base pairing

SL & HLSyllabus understandings: D1.1.2

Replication begins by separating the two strands of the parent molecule. Each single strand is then used as a template for a new strand. Every new DNA molecule therefore consists of:

  • one strand conserved from the parent molecule, and
  • one newly synthesised strand.

This is semi-conservative replication (“half-conserving”).

Why the copies are identical

New strands are assembled by complementary base pairing: adenine pairs only with thymine and guanine only with cytosine. So the base sequence of each new strand is decided by its template:

Strand Base sequence (written base for base under each other)
Parental strand 1 A C G T T G C
Parental strand 2 T G C A A C G
New strand on template 1 T G C A A C G (same as strand 2)
New strand on template 2 A C G T T G C (same as strand 1)

Each new strand is complementary to its template and identical to the other parental strand. Both daughter molecules therefore have the same base sequence as the original.

How this gives high accuracy

  • Only one base fits opposite each template base, so the chance of inserting the wrong one is very small.
  • A complete parental strand is kept in each molecule, so the original sequence is never lost: it is the reference against which the new strand is made (and, at higher level, checked).

Evidence: the Meselson–Stahl experiment

In 1958 Matthew Meselson and Franklin Stahl grew E. coli on the heavy isotope of nitrogen, ¹⁵N, then moved them to ordinary ¹⁴N and separated their DNA by density.

The Meselson–Stahl experiment
¹⁵N strand (heavy)¹⁴N strand (light)CsCl density gradientGen 0Gen 1Gen 2lighthybridheavylower density ↑higher density ↓Many generations in ¹⁵Nall DNA heavy (¹⁵N/¹⁵N)every molecule hybrid (¹⁵N/¹⁴N)half hybrid, half light (¹⁴N/¹⁴N)Parental strands stay intact.Spinning makes the CsCl solution denser towards the bottom of the tube.Each DNA molecule settles where its density equals that of the solution,so DNA containing ¹⁵N forms a band lower down than DNA with only ¹⁴N.Heavy band: both strands ¹⁵N. Hybrid band: one ¹⁵N and one ¹⁴N strand.Light band: both strands ¹⁴N.ModelGen 1Gen 2Predicted vs observedSemi-conservative✓ matches the resultsConservative✗ ruled out by generation 1Dispersive✗ ruled out by generation 2
Text description of this animation

Bacteria (E. coli) were grown for many generations in a medium whose only nitrogen source was the heavy isotope ¹⁵N, so all their DNA was heavy. They were then moved to a medium containing only ¹⁴N. DNA was extracted at intervals and spun at high speed in a caesium chloride solution, which forms a density gradient; each type of DNA settles as a band where its density matches the solution. Generation 0 gives one low (heavy) band. After one generation in ¹⁴N there is a single band of intermediate (hybrid) density. After two generations there are two bands of equal size, one hybrid and one light. The last step compares these results with the predictions of the conservative model (heavy and light bands after one generation, no hybrid) and the dispersive model (a single band that becomes lighter each generation): only semi-conservative replication fits.

  1. Generation 0 — all ¹⁵N. After many generations in ¹⁵N medium, all the bacterial DNA contains heavy nitrogen in both strands. Centrifuged in caesium chloride, it forms a single band low in the tube (heavy).
  2. One generation in ¹⁴N. The bacteria are moved to ¹⁴N medium and allowed to divide once. All the DNA now forms a single band halfway between heavy and light — every molecule is a hybrid of one ¹⁵N strand and one ¹⁴N strand.
  3. Two generations in ¹⁴N. After a second division there are two bands of equal size — one hybrid and one light (¹⁴N only). The original ¹⁵N strands are still intact, each now paired with a new ¹⁴N strand.
  4. Which model fits?. Conservative replication predicts heavy and light bands after one generation, but there was only a hybrid band. Dispersive replication predicts a single band after two generations, but there were two. Only semi-conservative replication predicts both results.

The single hybrid band after one generation ruled out conservative replication; the two bands (hybrid and light) after two generations ruled out dispersive replication.

Helicase and DNA polymerase

SL & HLSyllabus understandings: D1.1.3

The replication fork in 3D
A replication forkOn the right, the parental double helix. At the fork, helicase unwinds it and breaks the hydrogen bonds between the bases. To the left, each separated parental strand is a template: DNA polymerase links free nucleotides into a new strand complementary to it. Each daughter molecule has one parental strand and one new strand.1 · The replication forkparental DNA(double helix)helicase: unwinds,breaks H-bondstemplate (parental) strandtemplate (parental) strandnew strandnew strandDNA polymeraseDNA polymerasefree nucleotidesreplication forkEach daughter molecule = one parental strand + one new strand (semi-conservative).Leading and lagging strands in prokaryotesThe fork moves to the right. The lower new strand, the leading strand, is made continuously by DNA polymerase III from one RNA primer, towards the fork. The upper new strand, the lagging strand, is made away from the fork as Okazaki fragments, each started from an RNA primer laid by DNA primase. DNA polymerase I replaces primers with DNA, and DNA ligase seals the nicks between fragments. All new strands are built 5′ to 3′.2 · Leading and lagging strands (AHL)5′3′3′5′3′5′lagging strand: discontinuous (Okazaki fragments)helicaseprimaseDNA pol IIIDNA pol Ireplaces primerDNA ligaseseals nickRNA primersOkazaki fragmentleading strand: continuous, towards the forkRNA primerDNA pol IIIfork movesEvery new strand is built 5′ → 3′: nucleotides are added to the 3′ end.Template strands: parental (dark). New DNA: red. RNA primers: amber.

Parental strands are dark and new DNA is red, so each daughter molecule shows one of each.

Text description of this visual

A DNA molecule 24 base pairs long lies across the screen. On the right it is still a right-handed double helix of two antiparallel strands; the parental strands have dark backbones and bases coloured as in A1.2 (adenine blue, thymine orange, guanine green, cytosine purple), with two hydrogen bonds (dashed yellow) in each A–T pair and three in each G–C pair. A purple ring of helicase moves from left to right along the molecule, unwinding the helix and breaking the hydrogen bonds, so the two strands separate into the two arms of a Y-shaped replication fork. Free nucleotides gather, and DNA polymerase (blue) links nucleotides with bases complementary to each template strand into a new strand with a red backbone. When the whole molecule has been copied there are two double helices, each with one dark parental strand and one red new strand: replication is semi-conservative. A second model (higher level) shows the prokaryotic fork in detail — RNA primers (amber, with uracil) laid by DNA primase, the leading strand made continuously towards the fork, the lagging strand made away from the fork as Okazaki fragments, DNA polymerase I replacing primers with DNA, DNA ligase sealing the nick, and DNA polymerase III proofreading a mismatched base.

Replication fork

Helicase
A ring-shaped enzyme that moves along the DNA at the fork. It unwinds the double helix and breaks the hydrogen bonds between complementary bases, separating the two strands. It uses energy from ATP.
Replication fork
The Y-shaped region where the parental double helix is being separated into two single strands. It moves along the molecule as replication proceeds.
Parental double helix
The part of the original molecule not yet copied. Its two strands are antiparallel and held together by hydrogen bonds between complementary bases.
Hydrogen bonds
Dashed yellow sticks — two in each A–T pair and three in each G–C pair. They are weak individually, so helicase can break them without breaking the covalent bonds of the sugar–phosphate backbones.
Template strand
Each separated parental strand is a template. Its exposed bases determine the order of bases in the new strand, because each base can only pair with its complementary base.
Free nucleotides
Nucleotides carrying all four bases are present in the nucleoplasm (or cytoplasm in prokaryotes). They are the raw material for the new strands.
DNA polymerase
Moves along a template strand, adding nucleotides whose bases are complementary to the template and linking each one to the end of the new strand by a covalent bond in the sugar–phosphate backbone.
New strand
Built from free nucleotides (red backbone). Its base sequence is complementary to its template and identical to the other parental strand.
Conserved parental strand
Each daughter molecule keeps one complete strand from the parent molecule (dark backbone). It was not broken up or copied — it acted as the template.
Two daughter DNA molecules
Both daughter molecules have exactly the same base sequence as the original molecule and as each other. Each is one parental and one new strand.
A–T pair
Adenine (blue) pairs only with thymine (orange), held by two hydrogen bonds.
G–C pair
Guanine (green) pairs only with cytosine (purple), held by three hydrogen bonds.
  1. Helicase unwinds the helix. Helicase moves along the DNA, unwinding the double helix and breaking the hydrogen bonds between the complementary bases. The two strands separate, forming a Y-shaped replication fork. The covalent sugar–phosphate backbones are not broken.
  2. Each strand is a template. The bases on each separated strand are now exposed. Each parental strand acts as a template for a new strand. Free nucleotides with all four bases are available nearby.
  3. DNA polymerase builds new strands. DNA polymerase adds nucleotides one at a time, choosing each by complementary base pairing (A with T, G with C), and joins it to the new strand with a covalent bond. The two new strands are built in opposite directions because the templates are antiparallel.
  4. Two identical daughter molecules. When the whole molecule has been copied, each daughter DNA molecule consists of one parental strand (dark) and one new strand (red), which wind back into a double helix. This is semi-conservative replication. Both molecules have the same base sequence as the original. (Simplified — the enzymes are not shown and both new strands are drawn as continuous; the AHL model shows the lagging strand.)

Prokaryotic fork (AHL)

Helicase
Unwinds the double helix and breaks the hydrogen bonds at the fork. In bacteria it is a ring of six subunits that encircles one template strand and moves along it towards the fork.
Direction of the fork
The arrow shows the fork moving to the right. The upper template runs 5′→3′ towards the fork; the lower template runs 3′→5′ towards the fork.
DNA primase
Makes an RNA primer — a short length of RNA nucleotides — by complementary base pairing with the template. DNA polymerase III cannot start a new strand without one.
RNA primer
A short RNA sequence (amber backbone; uracil instead of thymine) with a free 3′ end to which DNA polymerase III can add DNA nucleotides. The leading strand needs only this one primer.
DNA polymerase III (leading strand)
Adds DNA nucleotides to the 3′ end of the primer and then of the growing strand, moving in the same direction as the fork, so the leading strand is made continuously.
DNA polymerase III (lagging strand)
Extends each lagging-strand primer 5′→3′, which means moving away from the fork, until it reaches the previous fragment. Then it starts again at a new primer near the fork.
Leading strand
The new strand whose 5′→3′ direction is towards the fork. It is synthesised continuously and needs only one RNA primer.
3′ end of the leading strand
New nucleotides are only ever added here. The phosphate on carbon 5′ of the incoming nucleotide is bonded to the –OH on carbon 3′ of the last nucleotide in the strand.
Lagging strand
The new strand whose 5′→3′ direction is away from the fork. It is synthesised discontinuously, as a series of Okazaki fragments, each needing its own primer.
Okazaki fragment
A short section of lagging strand made from one RNA primer (about 1000–2000 nucleotides in bacteria; much shorter here). Each fragment is started close to the fork and extended away from it.
DNA polymerase I
Removes the RNA nucleotides of a primer and replaces them with DNA nucleotides, working from the 3′ end of the next fragment. It cannot join the last nucleotide to the strand ahead, so it leaves a nick.
Nick
A break in the sugar–phosphate backbone between two adjacent nucleotides on the lagging strand — a missing covalent bond between a 3′–OH and the 5′ phosphate next to it.
DNA ligase
Seals each nick by forming the missing covalent (phosphodiester) bond in the sugar–phosphate backbone, joining the Okazaki fragments into one continuous strand.
Mismatched nucleotide
A nucleotide with guanine was added opposite thymine. It does not pair properly, so DNA polymerase III removes it from the 3′ end before adding the correct nucleotide, with adenine.
  1. Primase lays RNA primers. Helicase opens the fork. DNA primase makes a short RNA primer on each template, by complementary base pairing (uracil pairs with adenine). DNA polymerase III can only add nucleotides to an existing 3′ end, so it cannot start a strand without a primer.
  2. Leading strand — continuous. DNA polymerase III adds DNA nucleotides to the 3′ end of the leading-strand primer. Because this strand is made 5′→3′ towards the fork, the polymerase can follow the fork and synthesise it continuously. On the other template, Pol III extends the first lagging-strand primer away from the fork.
  3. Lagging strand — Okazaki fragments. As the fork opens more of the upper template, primase lays a new primer close to the fork. DNA polymerase III extends it away from the fork until it reaches the previous fragment. The lagging strand is made discontinuously, as Okazaki fragments, each with its own primer.
  4. DNA polymerase I replaces primers. DNA polymerase I removes the RNA nucleotides of the earlier primer one by one and replaces them with DNA nucleotides, extending the 3′ end of the newer fragment. It cannot join its last nucleotide to the DNA ahead, so a nick is left in the backbone.
  5. DNA ligase seals the nick. DNA ligase forms the missing covalent bond between the sugar of one nucleotide and the phosphate of the next, so the Okazaki fragments are joined into one continuous DNA strand.
  6. Proofreading by DNA polymerase III. DNA polymerase III adds a nucleotide with guanine opposite thymine — a mismatch. It detects the mispairing, removes the incorrect nucleotide from the 3′ end of the new strand, and then adds a nucleotide with the correct base (adenine). This greatly reduces errors in replication.

Replication is carried out by a team of enzymes working together at a replication fork, the Y-shaped region where the parent molecule is being separated. The fork moves along the molecule as copying proceeds. At standard level you need the roles of two enzymes.

Helicase

  • Moves along the DNA at the fork.
  • Unwinds the double helix.
  • Breaks the hydrogen bonds between complementary bases, separating the two strands.
  • Uses energy from ATP.

Only hydrogen bonds are broken: the covalent bonds of each sugar–phosphate backbone stay intact, so each strand remains a continuous template.

DNA polymerase

  • Moves along each template strand.
  • Adds free nucleotides one at a time, each with the base that is complementary to the next base on the template.
  • Links each new nucleotide to the end of the growing strand by a covalent bond between the sugar of one nucleotide and the phosphate of the next, forming the new sugar–phosphate backbone.

After synthesis, each template strand and its new partner wind together into a double helix, giving two daughter DNA molecules.

PCR and gel electrophoresis

SL & HLSyllabus understandings: D1.1.4

The polymerase chain reaction (PCR)

PCR amplifies a chosen DNA sequence, turning a tiny sample into millions or billions of copies. The tube contains:

  • the DNA sample (the template);
  • primers: two short, single-stranded DNA sequences complementary to the two ends of the target sequence, one for each strand;
  • free nucleotides with all four bases;
  • Taq polymerase, a DNA polymerase from Thermus aquaticus, a bacterium that lives in hot springs. It is heat-stable, so it is not denatured at 95 °C.

A thermocycler repeats a cycle of temperature changes, typically 25–35 times:

Stage Temperature What happens
Denaturation about 95 °C Hydrogen bonds break and the strands separate
Primer annealing about 55–65 °C Primers bind to complementary sequences on each single strand
Extension about 72 °C Taq polymerase extends each primer, building a complementary strand

Each cycle doubles the number of copies of the target: after n cycles, one molecule gives 2ⁿ copies (2³⁰ is over a billion).

Simulation The polymerase chain reaction
What is happening to one DNA molecule in this stageA double-stranded DNA molecule before the first cycle, with the target sequence between the two primer sites.Ready: DNA, primers, nucleotides, Taq25 °Ctarget sequence (between the primer sites)5′3′3′5′primerprimernew strand (5′→3′) →← new strand (5′→3′)
Cycles completed
0
Stage
—
Temperature
25 °C
Copies of the target
1
  1. Denaturation, about 95 °C. Heat breaks the hydrogen bonds between the bases, so the two strands of each DNA molecule separate.
  2. Primer annealing, about 60 °C. Cooling lets the two primers form hydrogen bonds with complementary sequences at the 3′ ends of the target region, one on each single strand.
  3. Extension, about 72 °C. Taq polymerase, which is not denatured at high temperature, adds nucleotides to the 3′ end of each primer, building a new strand complementary to each template.
Copies of the target DNA against number of PCR cycles, on a logarithmic scale0510152025303510⁰10²10⁴10⁶10⁸10¹⁰10¹²10¹⁴Number of cycles →Copies of target DNA (log scale) →

this run perfect doubling (shown when efficiency is below 100%)

Before the first cycle: 1 copy of the target sequence.

Show data table
CyclesCopies
01
532
101,024
1532,768
201.05 × 10⁶
253.36 × 10⁷
301.07 × 10⁹
353.44 × 10¹⁰

Simplified model. Each completed cycle copies a set share of the molecules (perfect PCR doubles them: start × 2ⁿ). Real reactions slow to a plateau after about 30 cycles as primers and nucleotides are used up. Temperatures are typical: the annealing temperature (about 50–65 °C) is chosen to suit the primers.

Text description of this simulation

A schematic of one DNA molecule in a PCR tube with a thermometer, and a counter. Pressing "Next stage" steps through a cycle: denaturation at about 95 °C separates the strands; primer annealing at about 60 °C lets two primers bind to the 3′ ends of the target sequence, one on each strand; extension at about 72 °C lets Taq polymerase build new strands from the primers. After each complete cycle the number of copies of the target doubles (start × 2ⁿ), shown on a graph with a logarithmic scale; after 30 cycles one molecule has become over a billion. Sliders set the number of cycles, the starting number of copies and the efficiency of each cycle.

Gel electrophoresis

Gel electrophoresis separates DNA fragments by size (length).

  1. Samples are loaded into wells at one end of an agarose gel, a mesh of polymer fibres in a buffer solution.
  2. A voltage is applied. DNA is negatively charged because of its phosphate groups, so it moves towards the positive electrode. The wells are therefore placed at the negative end.
  3. The gel mesh slows larger fragments more than smaller ones, so shorter fragments travel farther in the same time. Charge does not separate them, because it is proportional to length.
  4. The current is switched off before the smallest fragments run off the end; the DNA is stained so the bands can be seen. Each band is many fragments of the same length.
  5. A DNA ladder of fragments of known sizes is run in one lane, so the sizes of other bands can be estimated.

Applications: DNA profiling and more

SL & HLSyllabus understandings: D1.1.5

PCR and gel electrophoresis are used together in many fields. The most important example is DNA profiling.

DNA profiling

Human DNA contains short tandem repeats (STRs): places where a short sequence of a few bases is repeated many times. The number of repeats at each locus varies greatly between people, and each person has two versions (alleles), one from each parent.

  1. DNA is extracted from a sample (blood, hair roots, skin cells, saliva or semen). Only a tiny amount is needed.
  2. PCR amplifies a set of STR loci, using primers that bind either side of each repeat.
  3. Gel electrophoresis separates the products by length: more repeats make a longer fragment, which moves less far. The pattern of bands is the DNA profile.
Simulation Gel electrophoresis and DNA profiling
Agarose gel with a DNA ladder and four DNA profilesWells at the top, next to the negative electrode. DNA fragments have moved down towards the positive electrode; the smallest fragments have moved farthest.− negative electrode (wells)LadderCrime sceneSuspect 1Suspect 2Suspect 31002003004005007001000150020003000bp+ positive electrodeDNA moves this way ↓

Move the measuring line onto a band to estimate its size from the ladder.

Chance that an unrelated person matches at all 13 markers: about 1 in 10¹³.

After 60 minutes the fragments have separated by size. Ladder bands run from 3000 bp nearest the wells to 100 bp farthest away.

Check your conclusion

Suspect 2 has every band that is in the crime-scene sample, and no others, so their DNA profile matches. Suspects 1 and 3 share some bands with the sample but not all, so they are excluded as the source.

Qualitative model with invented profiles at three STR loci (two bands per person per locus). Distance travelled is taken to fall in proportion to log(fragment length), which is roughly true over the working range of an agarose gel. The match probability assumes each marker is shared by chance 1 time in 10 (illustrative).

Text description of this simulation

An agarose gel seen from above, with wells at the top next to the negative electrode. A DNA ladder of fragments of known size runs in the first lane next to four DNA profiles. Increasing the run time moves the negatively charged DNA towards the positive electrode, the smallest fragments farthest; if the gel runs too long the smallest fragments run off the end. A measuring line estimates the size of a band from the ladder. In the forensic case the crime-scene sample is compared with three suspects; in the paternity case a child is compared with the mother and two men. A slider shows how using more STR markers makes a chance match between unrelated people less likely.

  • Forensic investigations: a profile from a crime scene is compared with profiles from suspects (and victims). A match is strong evidence that the DNA came from that person; a mismatch at any locus excludes them.
  • Paternity cases: every band in a child’s profile must come from either the mother or the biological father. Ignore the child’s bands that match the mother; a man can be the father only if he has all the remaining bands.

Other applications

  • Diagnosing infections: tests for COVID-19 used RT-PCR, in which reverse transcriptase first copies the viral RNA into DNA, which PCR then amplifies; other pathogens are detected in the same way.
  • Genetic testing for alleles that cause disease, before birth or in adults.
  • Amplifying DNA for sequencing, for genetic modification, and from tiny or ancient samples in evolutionary studies.

DNA polymerases work in one direction

AHLSyllabus understandings: D1.1.6

Each strand of DNA has two different ends (see A1.2 Nucleic acids):

  • the 5′ end has a phosphate group attached to carbon 5′ of the last deoxyribose;
  • the 3′ end has a free –OH group on carbon 3′ of the last deoxyribose.

All the nucleotides in a strand point the same way, because every link in the backbone joins carbon 3′ of one sugar to the phosphate on carbon 5′ of the next.

The rule for DNA polymerases

DNA polymerases can only add nucleotides to the 3′ end of a strand. The phosphate on carbon 5′ of the incoming nucleotide is bonded to the –OH on carbon 3′ of the last nucleotide in the strand. So:

  • new strands always grow in the 5′→3′ direction;
  • because the new strand is antiparallel to its template, the polymerase moves along the template in the 3′→5′ direction;
  • the 5′ end of a strand is never extended.

Free nucleotides arrive as deoxynucleoside triphosphates. Two of the three phosphates are released as each nucleotide is added, which supplies the energy for the reaction.

A DNA polymerase also cannot start a new strand from nothing: it needs an existing 3′ end to add to. In the cell this is provided by an RNA primer.

Leading and lagging strands

AHLSyllabus understandings: D1.1.7

At a replication fork the two template strands are antiparallel, but both new strands must be built 5′→3′. The two strands are therefore made in different ways.

Leading strand: continuous

On one template, synthesis in the 5′→3′ direction runs towards the fork. DNA polymerase III can follow the fork as it opens, adding nucleotides without stopping. The leading strand is synthesised continuously, and an RNA primer is needed only once, at the start.

Lagging strand: discontinuous

On the other template, synthesis in the 5′→3′ direction runs away from the fork. As the fork opens, a new stretch of template is exposed behind the polymerase. Synthesis must keep restarting close to the fork with a new RNA primer, and each section is extended away from the fork until it meets the previous one. The lagging strand is therefore made discontinuously, as short sections called Okazaki fragments (about 1000–2000 nucleotides long in bacteria and 100–200 in eukaryotes).

Leading strand Lagging strand
Direction of synthesis relative to the fork towards away from
Synthesis continuous discontinuous (Okazaki fragments)
RNA primers needed one one per Okazaki fragment
Joining needed no yes, by DNA ligase

In bacteria replication starts at a single origin on the circular chromosome and two forks move away from it in opposite directions, each with its own leading and lagging strand.

Primase, DNA polymerase III, DNA polymerase I and ligase

AHLSyllabus understandings: D1.1.8

In prokaryotes, the main enzymes at the fork are:

Enzyme Function
Helicase Unwinds the double helix and breaks hydrogen bonds between bases at the fork
DNA primase Makes RNA primers — short RNA sequences complementary to the template — giving a free 3′ end to build on: once on the leading strand, repeatedly on the lagging strand
DNA polymerase III The main replicating enzyme: adds DNA nucleotides to the 3′ end of a primer and then of the growing strand, building the leading strand continuously and each Okazaki fragment
DNA polymerase I Removes the RNA nucleotides of each primer and replaces them with DNA nucleotides, extending the 3′ end of the adjacent, newer (fork-side) Okazaki fragment; it leaves a nick
DNA ligase Seals each nick by forming the missing covalent (sugar–phosphate) bond, joining Okazaki fragments into a continuous strand

Order of events on the lagging strand

  1. Primase lays an RNA primer near the fork.
  2. DNA polymerase III extends it away from the fork, making an Okazaki fragment, until it reaches the previous fragment’s primer.
  3. DNA polymerase I replaces that primer with DNA.
  4. DNA ligase seals the nick that remains.

Because the primers were made of RNA (with uracil and ribose), replacing them leaves the finished strand made entirely of DNA.

Proofreading by DNA polymerase III

AHLSyllabus understandings: D1.1.9

DNA polymerase III usually adds the correct nucleotide, but occasionally it inserts one whose base does not pair with the template, for example guanine opposite thymine. A mismatched base pair does not have the correct shape and hydrogen bonding.

Proofreading happens straight away:

  1. DNA polymerase III detects that the base pair it has just made is mismatched.
  2. It moves back and removes the incorrect nucleotide from the 3′ end of the new strand.
  3. It then adds a nucleotide with the correctly matched base and carries on.

Proofreading reduces the error rate of replication by roughly a hundredfold, to about one wrong base in ten million added. Other repair systems correct many of the remaining errors, but you only need to know proofreading by DNA polymerase III. Replication errors that are not corrected become mutations that are passed on when the cell divides (see D1.3 Mutation and gene editing).

The last step of the AHL model shows proofreading at the 3′ end of the leading strand.

Must-know definitions

DNA replication
The production of new DNA molecules with exactly the same base sequence as the original. It happens before every cell division, so it is needed for reproduction and, in multicellular organisms, for growth and tissue replacement.
Semi-conservative replication
Each new DNA molecule consists of one strand from the parent molecule (conserved) and one newly synthesised strand, made using the parental strand as a template.
Complementary base pairing
Adenine pairs only with thymine and guanine only with cytosine, so the base sequence of each new strand is set by its template. This makes copying highly accurate: each new strand is identical to the other parental strand.
Helicase
An enzyme that moves along DNA at the replication fork, unwinding the double helix and breaking the hydrogen bonds between complementary bases so that the two strands separate. It uses energy from ATP.
DNA polymerase
An enzyme that builds a new DNA strand on a template: it adds free nucleotides one at a time by complementary base pairing and links each to the growing strand with a covalent bond in the sugar–phosphate backbone.
Polymerase chain reaction (PCR)
A technique for making many copies of a chosen DNA sequence, using repeated cycles of denaturation (~95 °C), primer annealing (~55–65 °C) and extension (~72 °C) by heat-stable Taq polymerase. Each cycle doubles the number of copies.
Gel electrophoresis
Separation of DNA fragments by size: negatively charged DNA moves through a gel towards the positive electrode, and shorter fragments move through the mesh faster and so travel farther in the same time.
Directionality of DNA polymeraseAHL
DNA polymerases only add a nucleotide to the free 3′ end of a strand, bonding the phosphate on carbon 5′ of the incoming nucleotide to the –OH on carbon 3′ of the strand. Strands therefore grow 5′→3′.
Leading and lagging strandsAHL
The leading strand is synthesised continuously towards the fork from one RNA primer. The lagging strand is synthesised discontinuously away from the fork, as Okazaki fragments that each need their own primer.
ProofreadingAHL
DNA polymerase III checks each base pair as it is formed; if the nucleotide just added at the 3′ end is mismatched, it removes it and replaces it with a correctly matched nucleotide.

Common exam mistakes

  • Loses marks In semi-conservative replication, each new DNA molecule is half new because each strand is a mixture of old and new pieces.

    Write instead Each new molecule has one complete parental strand and one complete new strand. A mixture of old and new pieces within each strand is the dispersive model, which Meselson and Stahl ruled out.

  • Loses marks The new strand has the same base sequence as its template strand.

    Write instead The new strand is complementary to its template, so it has the same base sequence as the other parental strand. The two daughter molecules are identical to each other and to the original.

  • Loses marks Helicase breaks the DNA strands apart by breaking the sugar–phosphate backbone.

    Write instead Helicase breaks the hydrogen bonds between complementary bases, separating the two strands. The covalent bonds of each backbone stay intact, so each strand can act as a template.

  • Loses marks DNA moves towards the negative electrode in gel electrophoresis.

    Write instead DNA is negatively charged (its phosphate groups), so it moves away from the wells at the negative electrode towards the positive electrode.

  • Loses marks Smaller DNA fragments move faster in a gel because they carry more charge.

    Write instead Every nucleotide carries one negative charge, so charge is proportional to length. Smaller fragments move faster because they pass through the pores of the gel mesh more easily.

  • Loses marks Taq polymerase is used in PCR because it works faster at body temperature.

    Write instead Taq polymerase comes from Thermus aquaticus, a bacterium of hot springs, so it is not denatured by the repeated heating to about 95 °C, and its optimum (about 72 °C) is used for extension.

  • Loses marks If a man shares a band with a child, he must be the father.

    Write instead Every band in the child must come from the mother or the father. Remove the bands that match the mother; the biological father must have all of the remaining (paternal) bands, at every locus tested.

  • Loses marks The lagging strand is made 3′→5′, in the same direction as the fork.

    Write instead Both new strands are made 5′→3′. On the lagging strand this means working away from the fork, so it is made in short Okazaki fragments, each started from a new RNA primer.

    AHL
  • Loses marks DNA polymerase I joins the Okazaki fragments together.

    Write instead DNA polymerase I replaces the RNA primers with DNA but leaves a nick; DNA ligase seals each nick by forming the last covalent bond in the sugar–phosphate backbone.

    AHL
  • Loses marks Primers in DNA replication are short pieces of DNA, just like PCR primers.

    Write instead In the cell, DNA primase makes RNA primers (which are later replaced by DNA). The primers added to a PCR mixture are short single-stranded DNA sequences made artificially.

    AHL

Self-test

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Multiple-choice questions

  1. Question 1A DNA molecule consists of strands X and Y. It is replicated once. Which describes the base sequence of the new strand that was built using strand X as its template?
  2. Question 2In the Meselson–Stahl experiment, E. coli grown for many generations in ¹⁵N medium were transferred to ¹⁴N medium. If replication is semi-conservative, what fraction of the DNA molecules will be hybrid (¹⁵N/¹⁴N) after three generations in ¹⁴N?
  3. Question 3Which bonds are broken by helicase during DNA replication?
  4. Question 4Why is Taq polymerase, rather than DNA polymerase from human cells, used in the polymerase chain reaction?
  5. Question 5Why do DNA fragments of different lengths end up at different distances along an electrophoresis gel?
  6. Question 6STR fragments at one locus were separated by gel electrophoresis. The mother has bands at 150 and 320 bp; the child at 150 and 410 bp. Man A has bands at 200 and 320 bp, man B at 410 and 500 bp, and man C at 150 and 270 bp. Which man could be the child's biological father?
  7. Question 7AHLWhen DNA polymerase III adds a nucleotide to a growing strand, the phosphate of the incoming nucleotide is bonded to which part of the last nucleotide in the strand?
  8. Question 8AHLWhich statement about the lagging strand is correct?
  9. Question 9AHLA mutant bacterium makes a non-functional DNA ligase but its other replication enzymes work normally. What would be found in its newly replicated DNA?
  10. Question 10AHLDuring replication, DNA polymerase III adds a nucleotide with cytosine opposite adenine on the template. What happens next?

Flashcards

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Prompt

Why must DNA be replicated in living organisms?

Last reviewed 19 October 2026. Spotted a mistake? Report it.

Type at least 2 letters.